Position of Ascending and Descending Nodes

  • Thread starter Thread starter TheHarvesteR
  • Start date Start date
  • Tags Tags
    Nodes Position
Click For Summary
SUMMARY

This discussion focuses on determining the positions of ascending and descending nodes in orbital mechanics. The user successfully calculates the altitude at these nodes using the trajectory equation: r = h²/μ / (1 + e cos(ν)), where h is the angular momentum, μ is the geocentric gravitational constant, and e is the eccentricity. The method involves finding the true anomaly at the nodes by subtracting the argument of perigee from 360 degrees. This approach is essential for building an orbital visualization system that accurately places icons at key orbital points.

PREREQUISITES
  • Understanding of orbital mechanics concepts such as ascending and descending nodes
  • Familiarity with angular momentum and its calculation
  • Knowledge of the trajectory equation in orbital dynamics
  • Experience with vector mathematics, including cross and dot products
NEXT STEPS
  • Research the calculation of true anomaly in orbital mechanics
  • Learn about the geocentric gravitational constant (μ) and its applications
  • Explore the use of eccentricity vectors in determining orbital characteristics
  • Investigate advanced orbital visualization techniques and tools
USEFUL FOR

Aerospace engineers, orbital mechanics enthusiasts, and developers creating orbital visualization systems will benefit from this discussion.

TheHarvesteR
Messages
14
Reaction score
0
Hi again.

I'm trying to determine the position of an orbit's ascending and descending nodes here. I already have the Longitude of the ascending node, and a unit vector that points to it, so what I now need is a way to find out the actual distance of the node from the central body.

More specifically, I'm trying to find some way to determine what my "altitude" would be at the ascending and descending nodes. Or, the point at which the line of nodes intersects the orbit.

So far I haven't had much luck with this one, all I can find are directions for calculating the longitude of the ascendind node, but nothing about it's actual distance from the central body.

The reason I'm trying to find these points is that I'm building an orbital visualization system here, and I'm placing icons over the more important points of the orbit, like periapsis, apoapsis, object position, and ascending and descending nodes. All other points are accounted for, but I'm missing that one bit of information to correctly place AN and DN.

Any help would be greatly appreciated.

Thanks in advance,

Cheers
 
Astronomy news on Phys.org
How did you find a vector that pointed towards the ascending node?

The normal way is to take the cross product of unit vector k (which lies on the geocentric Z axis) and your angular momentum vector, which means you have the angular momentum vector and can calculate its magnitude.

How did you find a vector that points towards perigee?

The normal way is to create an eccentricity vector that's derived from the LaPlace vector.

You can use the dot product of the eccentricity vector and your line of nodes to find the cosine of true anomaly. The easier way would probably be to subtract your argument of perigee from 360 to actually find your true anomaly at the ascending node. Once you have your true anomaly, you can use the following version of the trajectory equation to find the magnitude of your radius at the ascending node.

r = \frac{h^2/\mu}{1 + e cos(\nu)}

with h being the magnitude of your angular momentum vector
mu being your geocentric gravitational constant
e being the magnitude of your eccentricity vector (or just your eccentricity if you're getting your info from elsets)

And your angular momentum vector is the cross product of the position vector and the velocity vector. Since it remains constant, you can calculate it anywhere in your orbit. It's easiest to calculate at perigee or apogee since the velocity vector is perpendicular to the position vector at those two points. In other words, at perigee and apogee, the magnitude of your angular momentum is just your radius times your velocity (with both measured in either meters & meters/sec or km and km/sec, depending on the units you want your final answer to be in).
 
Last edited:
BobG said:
The easier way would probably be to subtract your argument of perigee from 360 to actually find your true anomaly at the ascending node.

This just might work :)

I already have functions set up to get a position given a true anomaly angle, so if I can find the true anomaly of the nodes, I pretty much aready have their positions.

I'll give this a try now. I'll let you know how this goes.

Thanks! (BTW, I'm loving these forums :smile: )

Cheers
 
Worked perfect! So simple and elegant!

Thanks a million!

Cheers
 
https://en.wikipedia.org/wiki/MoM-z14 Any photon with energy above 24.6 eV is going to ionize any atom. K, L X-rays would certainly ionize atoms. https://www.scientificamerican.com/article/whats-the-most-distant-galaxy/ The James Webb Space Telescope has found the most distant galaxy ever seen, at the dawn of the cosmos. Again. https://www.skyatnightmagazine.com/news/webb-mom-z14 A Cosmic Miracle: A Remarkably Luminous Galaxy at zspec = 14.44 Confirmed with JWST...

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 6 ·
Replies
6
Views
9K
Replies
7
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 45 ·
2
Replies
45
Views
83K