Position of package when dropped from plane

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SUMMARY

The discussion centers on the physics problem of determining the position of a package dropped from a plane flying horizontally at 148 m/s from a height of 4510 m. The acceleration due to gravity is 9.8 m/s², and air resistance is neglected. The key conclusion is that the package will land ahead of the point directly below where it was dropped due to its initial horizontal velocity. The time taken for the package to reach the ground is calculated using the vertical motion equations.

PREREQUISITES
  • Understanding of projectile motion principles
  • Knowledge of kinematic equations, specifically for vertical motion
  • Ability to separate motion into horizontal and vertical components
  • Familiarity with basic physics concepts such as acceleration due to gravity
NEXT STEPS
  • Calculate the time of flight for the package using the equation: t = √(2h/g)
  • Determine the horizontal distance traveled by the package using the formula: d = vt
  • Explore the effects of air resistance on projectile motion
  • Study real-world applications of projectile motion in aviation and engineering
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Students studying physics, educators teaching projectile motion, and anyone interested in understanding the dynamics of objects in free fall.

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Homework Statement



A plane is flying horizontally with speed 148 m/s at a height 4510 m above the ground, when a package is dropped from the plane. The acceleration is 9.8 m/s^2. Neglecting air resistance, when the package hits the ground, the plane will be... ahead, directly above, or behind the package?

Homework Equations



v^2 = vi^2 + .5ax

The Attempt at a Solution



I tried to break it into x and y components, and solve for x in the horizontal direction, but I am really confused. Please help.
 
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What is the initial velocity of the package in the y-direction?
How much time the packet takes to reach the ground?
 

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