Possibilities for Set B with n Objects in Sample Space U

Click For Summary
SUMMARY

The discussion centers on determining the number of possible subsets for set B, given a sample space U with n objects and a subset A containing k objects, where A ∩ B ≠ ∅. The relevant formula for calculating the possibilities for B is established as 2n - 2n-k. Participants emphasize the importance of working through examples, such as using n = 3 and k = 2, to clarify the counting process and validate the formula. The conversation highlights the need to account for the intersection condition between sets A and B.

PREREQUISITES
  • Understanding of set theory concepts, including subsets and intersections.
  • Familiarity with the notation and properties of power sets.
  • Basic knowledge of combinatorial counting principles.
  • Ability to apply mathematical formulas to specific examples.
NEXT STEPS
  • Explore the derivation of the formula 2n - 2n-k for counting subsets.
  • Practice with additional examples using different values of n and k to reinforce understanding.
  • Study the properties of power sets and their applications in combinatorial problems.
  • Investigate related topics in set theory, such as Cartesian products and their implications for subset formation.
USEFUL FOR

Students studying discrete mathematics, mathematicians interested in combinatorial problems, and educators teaching set theory concepts.

agargento
Messages
38
Reaction score
2
Member warned that an attempt must be shown

Homework Statement


  1. Given sample space U with n objects. A ⊂ U, and A has k objects. A ∩ B ≠∅
What are all the possibilities for B?

Homework Equations



2n - All possibilities for set B with n objects

The Attempt at a Solution



I don't know where even to begin... The question itself confuses me.
 
Physics news on Phys.org
Hello again,

Entering a new subject area always takes some getting used to.
You write 'What are all the possibilities for B?' but I suppose (and hope) you mean 'How many B are possible? '

In the relevant equation the ∅ is included, right ? But is it a posssibility for B given that A ∩ B ≠∅ ?
Does the number k have influence on the answer ?
 
BvU said:
Hello again,

Entering a new subject area always takes some getting used to.
You write 'What are all the possibilities for B?' but I suppose (and hope) you mean 'How many B are possible? '

In the relevant equation the ∅ is included, right ? But is it a posssibility for B given that A ∩ B ≠∅ ?
Does the number k have influence on the answer ?

Yea, it should be "how many", just bad translation on my part. Didn't understand your other 2 questions. What is k in this question?
 
agargento said:
Yea, it should be "how many", just bad translation on my part. Didn't understand your other 2 questions. What is k in this question?
If you are stuck on this sort of problem, you should always try an example. Try ##n =3## and ##k =2##.
 
PeroK said:
If you are stuck on this sort of problem, you should always try an example. Try ##n =3## and ##k =2##.
Oh I got confused. I think the answer might be 2n-k ... But if A and B have something in common, subtracting k might subtract some objects that exist in B?
 
agargento said:
Oh I got confused. I think the answer might be 2n-k ... But if A and B have something in common, subtracting k might subtract some objects that exist in B?
You can check your formula with the example numbers I suggested.
 
PeroK said:
You can check your formula with the example numbers I suggested.

21 ? I still don't really get it.
 
agargento said:
21 ? I still don't really get it.
Why not do the example? It helps to work it out for some specific numbers. You should be able to list all possible sets for B and count them.
 
PeroK said:
Why not do the example? It helps to work it out for some specific numbers. You should be able to list all possible sets for B and count them.

Well ok... U has 3 objects. A has 2. Now, we know that B has something in common with A... But if we don't know the size of B, how can we know if it is equal to A, or maybe smaller?
 
  • #10
agargento said:
Well ok... U has 3 objects. A has 2. Now, we know that B has something in common with A... But if we don't know the size of B, how can we know if it is equal to A, or maybe smaller?
I don't think you understand this problem. It's asking you to count how many possibilities you have for B. You can go through all the options for B and count how many meet the requirements.
 
  • #11
PeroK said:
I don't think you understand this problem. It's asking you to count how many possibilities you have for B. You can go through all the options for B and count how many meet the requirements.

Clearly I'm very confused... if n=3 and k=2... Well, I think A could have 4 options... {1,2},{1},{2},{} ...
Seems to me B could be {1,2,3},{1,2},{1},{2},{3,2},{}... Which is 2n-2n-k...
 
  • #12
agargento said:
Clearly I'm very confused... if n=3 and k=2... Well, I think A could have 4 options... {1,2},{1},{2},{} ...
Seems to me B could be {1,2,3},{1,2},{1},{2},{3},{3,2}... Which is 2n-2n-k...
No. ##U## and ##A## are fixed. ##B## is the only "variable" set.
 
  • #13
PeroK said:
No. ##U## and ##A## are fixed. ##B## is the only "variable" set.
Hmm I see. So B could have 2 objects in common in A, or 1. It can also have another object... Maybe 2n? After all, B could be equal to A...
 
  • #14
agargento said:
Hmm I see. So B could have 2 objects in common in A, or 1. It can also have another object... Maybe 2n? After all, B could be equal to A...
That's all good, apart from another guess at the answer. You still haven't solved the problem for ##n = 3, k = 2##.

These problems are about finding a process or method for counting. That's why trying some examples is invaluable. It also gives you a test for any general answer you work out.
 
  • Like
Likes   Reactions: BvU
  • #15
PeroK said:
That's all good, apart from another guess at the answer. You still haven't solved the problem for ##n = 3, k = 2##.

These problems are about finding a process or method for counting. That's why trying some examples is invaluable. It also gives you a test for any general answer you work out.

Still can't wrap my head around this...umm.. If U has 3 objetcs, and A has two, B must have at least 1 object in common with A... So it can have either 1 or 2 objetcs that are in A, and maybe have another object from U... So... 2x2... =4 = 2k?
 
  • #16
For sure ##2^k## is a lower bound for the possibilities of B, because B can be any subset of A, in which case A∩B=B≠∅. But there are also other possibilities for B.
 
  • #17
agargento said:
Still can't wrap my head around this...umm.. If U has 3 objetcs, and A has two, B must have at least 1 object in common with A... So it can have either 1 or 2 objetcs that are in A, and maybe have another object from U... So... 2x2... =4 = 2k?

You need to write down all the possibilities for B.

1
2
3
1, 2
1, 3
2, 3
1, 2, 3

Assuming A is the set 1, 2 how many of the above possibilities for B meet the requirements?
 
  • #18
PeroK said:
You need to write down all the possibilities for B.

1
2
3
1, 2
1, 3
2, 3
1, 2, 3

Assuming A is the set 1, 2 how many of the above possibilities for B meet the requirements?

6... Which is 2n-2n-k
 
  • #19
agargento said:
6... Which is 2n-2n-k
Is that true in general, then? If so, why?
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
9
Views
2K