# Possible bound states of a one-dimensional square well I'm Lost

1. Oct 1, 2008

### messedmonk18

Possible bound states of a one-dimensional square well... I'm Lost!!!

1. The problem statement, all variables and given/known data
Find the solutions of even and odd parity from the transcendental equations then find the number of bound states that are possible for a potential such that p(max) = 4?

2. Relevant equations
p=ka/2 & p(max)^2 = (u(not)a$$^{2}$$/4), u(not) = $$\underline{2m(not)}$$$$\overline{\hbar^{2}}$$V(not)

I've found that for Even parity: p tan(p)= $$\sqrt{p(max)^{2}-p^{2}}$$

Odd: -p cot(p)= $$\sqrt{p(max)^{2}-p^{2}}$$

3. The attempt at a solution

So after I've found the Even and Odd solutions from a lot of algebra I'm completely lost on how to find the number of bound states. I assume that this has to do with integers of k but I'm not sure what this all means and how to derive a "bound" state from the information given. I need a lot of help... or at least some just to get started!

2. Oct 3, 2008

### malawi_glenn

Re: Possible bound states of a one-dimensional square well... I'm Lost!!!

what is p(max) = 4 ?