MHB Possible combinations for six digit license plates, numbers 0-9 and letters a-z.

AI Thread Summary
The discussion focuses on calculating the possible combinations for six-digit license plates using numbers 0-9 and letters a-z, specifically when three spots are limited to numbers and three to letters. The initial calculation of 3,895,584 is questioned, as it suggests no repetition is allowed. When allowing repetition, the correct approach involves calculating the permutations for numbers and letters separately, yielding 1,000 for numbers and 17,576 for letters. The total combinations are then determined by considering the arrangement of these letters and numbers, resulting in 351,520,000 unique license plates. The final conclusion emphasizes the importance of accounting for both repetition and positioning in the calculations.
Mackenzie3
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Hi,

I'm not sure if this is the correct forum so if I need to post elsewhere please let me know.

I'm having trouble with calculating the possible combinations for six digit license plates, numbers 0-9 and letters a-z.

I know the overall combinations are 1,947,792 when repetition is allowed and there are no other requirements, but I'm getting stuck when I have to limit three spots to only numbers and the other three to only letters.

I don't have a fancy calculator. Can someone let me know if this is correct?

10*9*8*26*25*24/6*5*4*3*2*1=3,895,584
 
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Mackenzie3 said:
Hi,

I'm not sure if this is the correct forum so if I need to post elsewhere please let me know.

I'm having trouble with calculating the possible combinations for six digit license plates, numbers 0-9 and letters a-z.

I know the overall combinations are 1,947,792 when repetition is allowed and there are no other requirements, but I'm getting stuck when I have to limit three spots to only numbers and the other three to only letters.

I don't have a fancy calculator. Can someone let me know if this is correct?

10*9*8*26*25*24/6*5*4*3*2*1=3,895,584

Is the only difference that three have to be numbers and three have to be letters? Because your calculation "10*9*8*26*25*24" suggests that repetition is not allowed.

However, if repetition is allowed and there must be three letters and three numbers, we can find all unique combinations as follows:

$10 \cdot 10 \cdot 10 = 1000$ number permutations
$26 \cdot 26 \cdot 26 = 17576$ letter permutations

But we're not done yet! Now we need to think about the positioning of the letters/numbers. So we need to see how many different ways the letters/numbers can be ordered.

What we want is to choose three places for, let's say, the letters (then the numbers will automatically take the other three positions). So we can order them in 6 choose 3 different ways.

${6 \choose 3} = \frac{6!}{3!(6-3)!}=20$

Then, finally, there are:

$1000 \cdot 17576 \cdot 20 = 351520000$ unique license plates.
 
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