Possible energy values given Hamiltonian

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The discussion focuses on finding the eigenvalues of a Hamiltonian matrix represented as H = [[a, b], [b, c]]. The user initially struggles with the determinant calculation for H - λI, leading to a complicated eigenvalue expression. Clarifications emphasize the importance of correctly identifying the eigenvalues of H rather than H - λI. Participants suggest showing detailed steps for deriving the quadratic equation and solving for λ, ultimately confirming the user's expression as correct but recommending simplification. The conversation highlights the intricacies of matrix algebra in quantum mechanics.
Rayan
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Homework Statement
The Hamiltonian for a two level system with the orthonormal states |1⟩ and |2⟩ is given by:
Relevant Equations
H = a|1⟩⟨1| + b|1⟩⟨2| + b|2⟩⟨1| + c|2⟩⟨2| ,

where a,b and c are real constants with energy unit.
So first I rewrote H as a matrix:

$$ H =
\begin{pmatrix}
a & b \\
b & c
\end{pmatrix} $$

And tried to find the eigenvalues/energies of H, so I solved

$$ det (H - \lambda I ) =
\begin{vmatrix}
a-\lambda & b \\
b & c-\lambda
\end{vmatrix} = (a-\lambda)(c-\lambda) - b^2 = ac - a\lambda - c\lambda + \lambda^2 - b^2 = 0
$$

but got a complicated solution

$$ \lambda = \frac{a+c}{2} \pm \sqrt{ ( \frac{a+c}{2} )^2 - (ac-b^2) } $$

What am I doing wrong here?
 
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Rayan said:
So first I rewrote H as a matrix:

$$ H =
\begin{pmatrix}
a & b \\
b & c
\end{pmatrix} $$
Ok.

Rayan said:
And tried to find the eigenvalues/energies of

$$ H - \lambda I $$
Terminology: You want the eigenvalues of ##H##, not ##H - \lambda I##.

Rayan said:
but got a complicated solution
$$ \lambda = \frac{a-c}{2} \pm \sqrt{ ( \frac{a-c}{2} )^2 - (ac-b^2) } $$
What am I doing wrong here?
It's hard to tell where you made the mistakes. Please show the steps in getting the quadratic equation for ##\lambda## and then the steps in solving for ##\lambda##.
 
TSny said:
Ok.Terminology: You want the eigenvalues of ##H##, not ##H - \lambda I##.It's hard to tell where you made the mistakes. Please show the steps in getting the quadratic equation for ##\lambda## and then the steps in solving for ##\lambda##.
You're right! I just updated my question with the steps!:)
 
Rayan said:
$$ det (H - \lambda I ) =
\begin{vmatrix}
a-\lambda & b \\
b & c-\lambda
\end{vmatrix} = (a-\lambda)(c-\lambda) - b^2 = ac - a\lambda - c\lambda + \lambda^2 - b^2 = 0
$$
This looks good.

Rayan said:
but got a complicated solution

$$ \lambda = \frac{a+c}{2} \pm \sqrt{ ( \frac{a+c}{2} )^2 - (ac-b^2) } $$
This looks correct.

My preference would be to write what you have as $$ \lambda = \frac{a+c}{2} \pm \frac1 2 \sqrt{ ((a+c)^2 - 4(ac-b^2) } $$
You should be able to simplify the expression inside the square root a little. (Work with the terms involving ##a## and ##c##.)
 
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