Possible energy values given Hamiltonian

Rayan
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Homework Statement
The Hamiltonian for a two level system with the orthonormal states |1⟩ and |2⟩ is given by:
Relevant Equations
H = a|1⟩⟨1| + b|1⟩⟨2| + b|2⟩⟨1| + c|2⟩⟨2| ,

where a,b and c are real constants with energy unit.
So first I rewrote H as a matrix:

$$ H =
\begin{pmatrix}
a & b \\
b & c
\end{pmatrix} $$

And tried to find the eigenvalues/energies of H, so I solved

$$ det (H - \lambda I ) =
\begin{vmatrix}
a-\lambda & b \\
b & c-\lambda
\end{vmatrix} = (a-\lambda)(c-\lambda) - b^2 = ac - a\lambda - c\lambda + \lambda^2 - b^2 = 0
$$

but got a complicated solution

$$ \lambda = \frac{a+c}{2} \pm \sqrt{ ( \frac{a+c}{2} )^2 - (ac-b^2) } $$

What am I doing wrong here?
 
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Rayan said:
So first I rewrote H as a matrix:

$$ H =
\begin{pmatrix}
a & b \\
b & c
\end{pmatrix} $$
Ok.

Rayan said:
And tried to find the eigenvalues/energies of

$$ H - \lambda I $$
Terminology: You want the eigenvalues of ##H##, not ##H - \lambda I##.

Rayan said:
but got a complicated solution
$$ \lambda = \frac{a-c}{2} \pm \sqrt{ ( \frac{a-c}{2} )^2 - (ac-b^2) } $$
What am I doing wrong here?
It's hard to tell where you made the mistakes. Please show the steps in getting the quadratic equation for ##\lambda## and then the steps in solving for ##\lambda##.
 
TSny said:
Ok.Terminology: You want the eigenvalues of ##H##, not ##H - \lambda I##.It's hard to tell where you made the mistakes. Please show the steps in getting the quadratic equation for ##\lambda## and then the steps in solving for ##\lambda##.
You're right! I just updated my question with the steps!:)
 
Rayan said:
$$ det (H - \lambda I ) =
\begin{vmatrix}
a-\lambda & b \\
b & c-\lambda
\end{vmatrix} = (a-\lambda)(c-\lambda) - b^2 = ac - a\lambda - c\lambda + \lambda^2 - b^2 = 0
$$
This looks good.

Rayan said:
but got a complicated solution

$$ \lambda = \frac{a+c}{2} \pm \sqrt{ ( \frac{a+c}{2} )^2 - (ac-b^2) } $$
This looks correct.

My preference would be to write what you have as $$ \lambda = \frac{a+c}{2} \pm \frac1 2 \sqrt{ ((a+c)^2 - 4(ac-b^2) } $$
You should be able to simplify the expression inside the square root a little. (Work with the terms involving ##a## and ##c##.)
 
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