Possible Values for Preimage Count in Meromorphic Functions on Riemann Sphere?

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The discussion focuses on identifying meromorphic functions on the Riemann Sphere, specifically those satisfying the equation f(f) = f. Participants conclude that the only valid solutions are the identity map and constant maps, with the identity map being the only meromorphic function that can satisfy f(f) = f. Additionally, the conversation explores the preimage count for meromorphic functions, questioning the possible values for n when f: sigma -> sigma has a preimage f^-1(c) containing precisely n elements. Key insights include the relationship between the degree of composition and the nature of meromorphic functions.

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  • Familiarity with the concept of function composition and degrees
  • Knowledge of the identity map and constant maps in complex analysis
  • Basic principles of Laurent series expansions
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Hi there,
working on some basic questions involving the Riemann Sphere(sigma): C union infinity

firstly, i was asked to find all meromorphic f: sigma -> sigma such that f(f)=f.

my thoughts are: since the degree of a composition f(g) is deg(f)deg(g), our only possibilities are f=identity map (whose degree is 1) or f=the constant map...but then the map f(z)= infinity is not meromorphic...
was also thinking that f(f)=f only when f^2=f which implies that f=f^-1...which only occurs with the identity map...secondly, let f: sigma->sigma be meromorphic and such that for each c belonging to sigma the preimage f^-1(c) contains precisely n elements(not counting multiplicities). what are the possible values for n??
stuck here, any hints would be great!
thank you.
 
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Ant farm said:
Hi there,
working on some basic questions involving the Riemann Sphere(sigma): C union infinity

firstly, i was asked to find all meromorphic f: sigma -> sigma such that f(f)=f.

my thoughts are: since the degree of a composition f(g) is deg(f)deg(g), our only possibilities are f=identity map (whose degree is 1) or f=the constant map...but then the map f(z)= infinity is not meromorphic...
was also thinking that f(f)=f only when f^2=f which implies that f=f^-1...which only occurs with the identity map...


f^2=f does not imply f=f^-1. Firstly, f^-1 need not exist, indeed cannot exist, unless f=Id. There are also more maps than just Id that satisfy f=f^-1 (or f^2=Id).



secondly, let f: sigma->sigma be meromorphic and such that for each c belonging to sigma the preimage f^-1(c) contains precisely n elements(not counting multiplicities). what are the possible values for n??
stuck here, any hints would be great!
thank you.


My first thoughts are that meromorphic functions have Laurent expansions.
 
it seems you have proved that f(f) = f implies degf = 1 or 0.that does sound as if f is id or constant, can you prove that?
 

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