Potential and Kinetic energy and a sled

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SUMMARY

The discussion focuses on the calculation of potential and kinetic energy for a sled and rider with a combined mass of 50 kg at a height of 15 m. The potential energy (PE) at the top of the hill is calculated using the formula PE = mgh, resulting in 7350 J. The total mechanical energy at the top, combining initial kinetic energy (KE) of 1600 J and potential energy, totals 8950 J. Ignoring friction, the kinetic energy at the bottom of the hill can be derived from the conservation of energy principle, confirming that total energy remains constant throughout the descent.

PREREQUISITES
  • Understanding of gravitational potential energy (PE = mgh)
  • Knowledge of kinetic energy (KE = 0.5 * m * v^2)
  • Familiarity with the conservation of mechanical energy principle
  • Basic algebra for solving equations
NEXT STEPS
  • Study the conservation of energy in mechanical systems
  • Learn how to calculate kinetic energy using velocity
  • Explore the effects of friction on energy calculations
  • Investigate real-world applications of potential and kinetic energy in physics
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Students studying physics, educators teaching energy concepts, and anyone interested in understanding the principles of mechanical energy in motion.

Red04Cobra
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A sled and rider with a combined mass of 50kg are at the top of a hill that is 15m above the level ground. The sled is given a push providing an initial kinetic energy at the top of the hill of 1600J.

A: choosing a reference level at the bottom of the hill what is the potential energy of the sled and rider at the top of the hill?

B: After the push what is the total mechanical energy of the sled and rider at the top of the hill?

C: If friction is ignored what will be the kinetic energy of the sled and rider at the bottom of the hill?


So far I have this..and I'm not sure if it's right.

PE=mgh PE= (50kg)*(9.8m/sec squared)*(15m) = 7350J
E=PE+KE 1600J+7350J = 8950J

after that I'm not really sure. Any help is greatly appreciated!
 
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You know the total energy, and if no work is done (draw a free body diagram if you want to verify this)...then the energy in the beginning is equal to the energy at the end...

You know the potential energy at the end (h = 0)...so all you have is one unknown (the velocity).
 
So..if I take (2*KE)/m and take the square root that would be right?
 
well, not KE (assuming you mean Kinetic Energy), but Total Energy...

(2*Total Energy) \ m and take the square root
 

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