Potential difference across capacitor in a network

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Suyash Singh

Homework Statement


Determine the potential difference across the plates of the capacitor of the network shown in the figure.

Circuit schematic of a single loop with two batteries labelled E1 (left) and E2 (right), and two capacitors labelled C1 (top) and C2 (bottom); charges -q and +q are marked on the plates of C1 and +q and -q on the plates of C2.

Homework Equations


kirchoff's loop rule
q=vc
3. The attempt at a solutio
applying kirchhoffs law
starting at bottom right point,
q/c2-E1+q/c1+E2=0
=>E2-E1=-q/c1-q/c2
now i am confused what to do further

the answer is
V1=-q/c1 and V2=q/c2
 
You don't need Kirchoff's law. Look at the second of the two relevant equations that you wrote down. Give q and c, what is v?
 
phyzguy said:
You don't need Kirchoff's law. Look at the second of the two relevant equations that you wrote down. Give q and c, what is v?
v=q/c
but why is v1 negative and v2 positive?
 
Suyash Singh said:
v=q/c
but why is v1 negative and v2 positive?
Negative or positive with respect to what?
Looks like they are assuming the ground to be at the negative terminal of E2.
 
+1

I think it is a badly written question. Is that the exact wording?
 
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CWatters said:
+1

I think it is a badly written question. Is that the exact wording?
yes it was asked in All India CBSE board 2013.
 
cnh1995 said:
Negative or positive with respect to what?
Looks like they are assuming the ground to be at the negative terminal of E2.
the ground is taken at zero potential in our syllabus.
 
Even if the 0V node was specified the polarity of the voltages isn't defined. Consider this circuit...

Circuit schematic of a battery with its + terminal at top in a loop with a resistor on the right, bottom wire grounded to 0V; arrows labelled E1, V2 (pointing down) and V3 (pointing up) sit beside the resistor.


If E1 = 10V then V3 = 10V and V2 = -10V. See how the polarity depends on the direction of the arrow I drew on the circuit.

So I would argue that in your circuit all of the following are valid answers...

V1=+q/c1 and V2=+q/c2
V1=-q/c1 and V2=+q/c2
V1=+q/c1 and V2=-q/c2
V1=-q/c1, and V2=-q/c2
 
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