Potential Difference Across Resistor (RC Circuit)?

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SUMMARY

The discussion focuses on calculating the potential difference across a resistor in an RC circuit with a resistance of 1M Ohm, a capacitance of 1 Micro Farad, and a voltage source of 30 V. The correct formula to use is V = E (1 - e^(-t/RC)). After 10 seconds, the expected voltage across the resistor should be 4V, indicating that the capacitor is charging and the voltage across the resistor is decreasing. The confusion arises from the interpretation of the charging process, where the voltage across the resistor approaches zero as the capacitor fully charges.

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  • Understanding of RC circuit theory
  • Familiarity with the exponential charging equation V = E (1 - e^(-t/RC))
  • Basic knowledge of voltage, resistance, and capacitance
  • Ability to perform calculations involving time constants in RC circuits
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  • Study the concept of time constant in RC circuits
  • Learn about capacitor charging and discharging processes
  • Explore the implications of resistor-capacitor series circuits on voltage behavior
  • Investigate the effects of varying resistance and capacitance on circuit performance
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Students studying electrical engineering, educators teaching circuit theory, and hobbyists working with RC circuits who seek to understand voltage behavior over time.

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Homework Statement



For the RC Circuit (R = 1M Ohm, C = 1 Micro Farad and E = 30 V) find the potential difference across the resistor 10 sec after the switch is closed.

Homework Equations



V = E (1 - e^ -t/RC)

The Attempt at a Solution



I use the above equation but I get it wrong (it should be 4V) I think I might be putting in something wrong.
 
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I think there is something wrong with your numbers and equation, because if the context is charging the capacitor with the resistor in series, the capacitor would be charged in 10 seconds, and the voltage across the resistor would have decreased to zero. But in your equation, the voltage (V) would approach 30V, so it doesn't make sense.
 

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