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Potential Difference in Circuits

  1. Sep 15, 2014 #1
    In the picture that i attached
    i need some help
    ********
    In the book it says
    ''' The negative terminal of the battery E_1 is connected to b. So at the lower end of the resistance R_2 the pd is 6V. "'
    What is the significance of this statement?
     

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    Last edited: Sep 15, 2014
  2. jcsd
  3. Sep 15, 2014 #2
    where's the picture?
     
  4. Sep 15, 2014 #3
    check attachments
     
  5. Sep 15, 2014 #4
    Does it give values for R1 and R2? Is there a ground point in the circuit?
     
  6. Sep 15, 2014 #5
    R_1 is 2 ohm
    nd R_2 is 4 ohm
     
  7. Sep 15, 2014 #6
    I just can't grasp what you are getting at. Are you saying why the pd between the negative end of E1 and the lower end of resistor R2 is claimed to be 6v?
     
  8. Sep 15, 2014 #7

    sophiecentaur

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    Gold Member

    The statement is a bit sloppy because it uses "PD", which should explicitly specify two points in the circuit, between which there is a Difference in Potential.
    If E2 is a 6V battery then, relative to point b, how can the Potential be anything but 6V? It's just stating the obvious, really, and can be used as a start in calculating the current and volts around the network.
     
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