- #1

Black Armadillo

- 12

- 0

## Homework Statement

The capacitors in the Figure are initially uncharged and are connected, as in the diagram, with switch S open. The applied potential difference is V_ab = + 210V

What is the potential difference V_ad after switch S is closed?

## Homework Equations

Q=C_eq*V

V_ab=Q/C

## The Attempt at a Solution

I really have no idea how to get started doing this problem. The first part of the problem asked "What is the potential difference V_cd?" This I found easy but once you close the switch I'm not sure how to approach the problem. Specifically how do you go about combining the capacitors to get a C_eq. Thanks for any help.