1. The problem statement, all variables and given/known data A 10.0 kg block is released from point A in Figure P8.57. The track is frictionless except for the portion BC, with a length of 6.00 m. The block travels down the track, hits a spring of force constant k = 2250 N/m, and compresses it 0.300 m from its equilibrium position before coming to rest momentarily. Determine the coefficient of kinetic friction between surface BC and the block. image can be found here: http://www.webassign.net/sb5/p8-57.gif 2. Relevant equations Ug=mgh Uel=(1/2)kx^2 K=(1/2)mv^2 w=FΔx Fk=μmg 3. The attempt at a solution initial potential energy - work done by friction = final elastic energy Ug - Work by friction = Uel mgh - FΔx = (1/2)kx^2 mgh - μmgΔx = (1/2)kx^2 μ = [mgh - (1/2)kx^2]/(mgΔx) plugging in the numbers… μ = [(10 kg)(9.8 m/s^2)(3 m) - .5(2025 N/m)(.3 m)^2]/[(10 kg)(9.8 m/s^2)(6 m)] and I got μ= 0.345, but this is incorrect and I am not sure why. Can someone please help point out my errors? Thanks!