Potential Energy and Work done to lift object distance h

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SUMMARY

The discussion focuses on calculating the height to which a 1 kg object can be lifted using the energy generated by a 0.10 kW light bulb over 12 minutes. The calculation involves converting power from kilowatts to watts and time from minutes to seconds, resulting in a total work output of 72,000 joules. Using the formula for potential energy (PE = mgh), the height (h) is determined to be 7347 meters, based on a gravitational constant of 9.8 m/s². This result, while mathematically correct, raises questions about its practical feasibility.

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  • Familiarity with the formulas for power, work, and gravitational potential energy
  • Ability to perform unit conversions (e.g., kW to watts, minutes to seconds)
  • Knowledge of gravitational acceleration (9.8 m/s²)
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Potential Energy and Work done to lift object distance "h"

The amount of energy needed to power a 0.10 kW bulb for 12 minutes would be sufficient to lift a 1 kg object how high?

Power = work/time
PE = mgh

First I converted kw to watts which is 100 watts. Then converted minutes to seconds = 720 seconds.
I found the work done by the lightbulb:

power = work/time
100 = w/720
w = 72,000 joules

Then I plugged that into potential energy(not sure if you can do that), I solved for h using 9.8 for gravity and 1 kg for mass

PE = mgh

72,000 = (1)(9.8)h

h = 7347 meters

That number seems a bit high
 
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That looks good to me.
 
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