Potential Energy as a function of x

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[SOLVED] Potential Energy as a function of x

Homework Statement


Take U = 5 at x = 0 and calculate potential energy as a function of x, corresponding to the force:
[tex]8e^{-2x}[/tex]


Homework Equations


[tex]W_{net} = U_i - U_f[/tex]
[tex]W = \int_a^b F_x dx[/tex]



The Attempt at a Solution



[tex]\int 8e^{-2x} dx = -4e^{-2x} = W(x)[/tex]

[tex]W(x) = -4e^{-2x} = U_i(x) - U_f(x)[/tex]
[tex]U_f(x) = U_i(x) + 4e^{-2x}[/tex]
[tex]U_f(x) = 5 + 4e^{-2x}[/tex]

correct answer: U(x) = [tex]1 + 4e^{-2x}[/tex]

Any ideas how i went wrong?
 
Last edited:
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You were working with definite integral, I guess. when you integrated 8exp(-2x), you should have put the limits (x = 0 and x = x).
 
SOLVED

[tex]W(x) = \int 8e^{-2x} = -4e^{-2x} + C[/tex] ( I forgot the C earlier)
[tex]W(x) = U_i(x) - U_f(x)[/tex]
[tex]-4e^{-2x} + C = 5 - U_f(x)[/tex]
[tex]U_f(x) = 5 - 4e^{-2x} - C[/tex]

SOLVE FOR C

U(0) = 5 = 5 - 4(1) - C
C = 4

SOLVE FOR U(x)

[tex]U_f(x) = 5 - 4e^{-2x} - 4[/tex]

[tex]U_f(x) = 1 - 4e^{-2x}[/tex]
 
Sourabh N said:
You were working with definite integral, I guess. when you integrated 8exp(-2x), you should have put the limits (x = 0 and x = x).

I am going to try this way as well when I get back from eating. Cheers!
 

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