Potential Energy Function problem ()

Click For Summary

Homework Help Overview

The problem involves a conservative force acting on an object in the xy-plane, described by a potential-energy function U(x, y) = a*(1 / x² + 1 / y²). The objective is to derive an expression for the force F in terms of unit vectors i and j.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the need to take partial derivatives of the potential-energy function to find the force. There is uncertainty regarding the variable "a" and its role in the final expression for F, with suggestions to rename it to "alpha" or modify its value.

Discussion Status

The discussion is ongoing, with participants exploring the implications of the variable "a" and its potential renaming. Some guidance has been offered regarding the evaluation of the gradient, but the exact issue with the computer's feedback remains unclear.

Contextual Notes

Participants note that the computer system may have specific requirements for variable naming or formatting that are causing confusion in the evaluation of the answer.

ccsmarty
Messages
17
Reaction score
0

Homework Statement



An object moving in the xy-plane is acted on by a conservative force described by the potential-energy function U(x, y)= a*(1 / x^{2}+1 / y^{2}), where a is a positive constant. Derive an expression for the force F expressed in terms of the unit vectors i and j.

Homework Equations



Gradient vectors, Partial derivatives

The Attempt at a Solution



I know I have to take the partial derivatives w.r.t. "x" and "y". But when I did that I came up with F = [(2a)/(x^3)]i + [(2a)/(y^3)]j. But the computer says: "The correct answer does not depend on the variable: a." But if I take the a out, it tells me that: "The correct answer involves the variable alpha, which was not part of your answer."
Any ideas??
Thanks in advance
 
Physics news on Phys.org
rename "a" as "alpha" ... maybe "2a" ... ?
 
^ bump
 
You aren't being ignored: I think we just aren't sure what the computer doesn't like...

It looks like you've evaluated the gradient of U and expressed the components of F correctly. The issue seems to be what "a" was in the potential function you posted. Is that supposed to be [tex]\alpha[/tex]? Computer entry systems are notoriously finicky. (Curse them!)
 

Similar threads

  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
1
Views
3K
  • · Replies 14 ·
Replies
14
Views
2K
Replies
15
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 13 ·
Replies
13
Views
3K