Potential energy of a dipole point and point charge

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SUMMARY

The discussion focuses on calculating the potential energy (U) of a system consisting of a point dipole (p) at the origin and a point charge (q) at position r. Two methods are employed: treating the dipole as a source in its own field and the charge as a test charge, and vice versa. The potential V(r) is derived as V(r) = p·r/(4πε0r^3), leading to the electric field E(r) = 3p cos(θ)/(4πε0r^3). The final expression for potential energy is U = -3p² cos(θ)/(4πε0r^3), although the user expresses confusion regarding the application of the energy formulas.

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  • Understanding of electric dipoles and point charges
  • Familiarity with potential energy equations in electrostatics
  • Knowledge of vector calculus, particularly gradient operations
  • Proficiency in using ε0 (vacuum permittivity) in electrostatic calculations
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  • Study the derivation of electric fields from potentials in electrostatics
  • Learn about the interaction between dipoles and external electric fields
  • Explore the concept of potential energy in different electrostatic configurations
  • Review the mathematical treatment of gradients and their physical interpretations
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Students and professionals in physics, particularly those studying electrostatics, electromagnetism, or preparing for advanced examinations in these fields.

hansbahia
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Homework Statement


A point dipole p is at the origin of coordinates, while a point charge q is at position r. Calculate the potential energy U of this system in two ways (a) by treating the dipole as a source and q as a test charge in the dipole field (b) by treating the dipole as a test-object in the Coulomb electric field of the point-charge, now treated as a source


Homework Equations


U=-pE
V(r)=Integral of Edr

The Attempt at a Solution


I found the potential

V(r)=p.r/(4πε0r^3)=p.r(hat)/(4πε0r^2)=pcosθ/(4πε0r^2)

Then I differentiated since E(r)=d/dr(V(r))

E(r)=-d/dr(V(r))=-d/dr(pcosθ/(4πε0r^2))=-(-3pcosθ/(4πε0r^3))=3pcosθ/(4πε0r^3)

So my U would be equal

U=-pE=-p(3pcosθ/(4πε0r^3))=-3p^2cosθ/(4πε0r^3) ?

It doesn't make sense
 
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First, \vec{E}= -\nabla \Phi \ne -\frac{\partial \Phi}{\partial r}.
Second, the energy of a charge q in potential V is U=qV.
Third, the energy of a dipole p in field E is U=-\vec{p}\cdot\vec{E}.
For part a, you're supposed to use a charge q in a dipole field.
For part b, you're supposed to use a dipole \vec{p} in point charge field.
 
Thank you!
 

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