Potential energy of gravitational force

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SUMMARY

The discussion focuses on calculating the potential energy of a bead of mass m sliding along the x-axis between two gravitational spheres of mass M, positioned equidistantly at distance d. The potential energy is derived using the gravitational force equation F_{grav} = \frac{-GMm}{r^2} and integrating to find U = \frac{GMm}{r^2}*{R_{M}}^2*(\frac{1}{R_{M}} - \frac{1}{r}). The bead's speed at the origin is determined after being released from x = 3d, and the frequency of small oscillations about the origin is also calculated. The discussion emphasizes the cancellation of the y components of gravitational forces due to symmetry.

PREREQUISITES
  • Understanding of gravitational force equations, specifically F_{grav} = \frac{-GMm}{r^2}
  • Knowledge of potential energy concepts, particularly U = -\int F dx
  • Familiarity with kinetic energy equations, K = \frac{1}{2}mv^2
  • Basic calculus for integration and understanding of oscillatory motion
NEXT STEPS
  • Study gravitational potential energy calculations in multi-body systems
  • Learn about the dynamics of oscillations and small oscillation frequency calculations
  • Explore the implications of symmetry in gravitational systems
  • Investigate advanced integration techniques for physics applications
USEFUL FOR

Students in physics, particularly those studying mechanics and gravitational forces, as well as educators looking for examples of potential energy and oscillation calculations.

diablo2121
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Homework Statement


A bead of mass m slides along the x-axis between two spheres of mass M equidistant from the x-axis (distance d) and attract the bead gravitationally.

a. Find the potential energy of the bead.

b. The bead is released at x = 3d with an initial velocity toward the origin. Find the speed at the origin.

c. Find the frequency of small oscillations of the bead about the origin.

Homework Equations


[tex]U = -\int F dx[/tex]

[tex]F_{grav} = \frac{-GMm}{r^2}[/tex]

[tex]E = U + K[/tex]

[tex]K = \frac{1}{2}mv^2[/tex]

The Attempt at a Solution


Integrating the force of gravity, I find that the potential energy of the force is [tex]\frac{GMm}{r^2}*{R_{M}}^2*(\frac{1}{R_{M}} - \frac{1}{r})[/tex] where [tex]r[/tex] is the distance straight from [tex]m[/tex] to one of the spheres [tex]M[/tex] and [tex]R_M[/tex] is the radius of [tex]M[/tex]. This is fine, but I'm stuck on how to set the potential in terms of d, which I will need to find the velocity in the next part.

Conceptually, I know the y component of the gravitational forces cancel out since the spheres are equal mass and distance away. Also, the potential I get for the x component will need to be doubled since there are two masses.
 
Last edited:
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Wow, once you learn Latex, it's a lot easier to format your equations. I hope that helps the equations a little better to understand.
 
Isn't the r distance really given by

[tex]r = \sqrt{x^2 + \frac{d^2}{4}}[/tex]
 

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