Let's hope my math is correct here.
1 horsepower = 745.7 watts, so 178,000 hp = 132,734,577 watts, or just about 133 MW.
1 watt is 1 joule per second, so 133 MW is 133 million joules per second.
Let's assume a 12-hour runtime and a 12-hour downtime to 'recharge'.
Twelve hours is 43,200 seconds, which means we need 5.745 TJ of energy.
Let's use gravitational potential energy and assume a maximum drop of 100 meters.
Near Earth's surface, the equation for GPE is ##U=mgh## where ##U## is the potential energy, ##m## is the mass, ##g## is the acceleration of Earth's gravity near the surface, which is 9.81 m/s2, and ##h## is the height. Our rearranged equation to solve for ##m## is ##m=\frac{U}{hg}##.
Plugging in our numbers, we get about 5.86x109 kg, or 5.86 million metric tons.
So a mass of 5.86 million tons, falling over a height of 100 meters, will provide 178 MW of power for 12 hours assuming no losses in your generator and that the entire setup is geared correctly to get the correct drop rate.
For comparison, 5.86 million tons is 5.86 billion liters of water. This is a cube of water 180 meters to a side, or nearly two football fields long, wide, and tall.
Luckily, large generators (not turbines) are about 95% efficient, so assuming a small loss in our gearing, our mass wouldn't need to increase drastically over what I've given here to account for inefficiencies. Unfortunately you'd be hard pressed to design and build the equipment to suspend this enormous mass and all the gearing to convert its linear drop into rotational motion for a generator. It's the equivalent of suspending almost 2,000 fully fueled Saturn V rockets, or about 100 Iowa-class battleships.