What Determines the Direction of Potential Gradient?

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SUMMARY

The discussion centers on determining the direction of the potential gradient in relation to electric fields and equipotential surfaces. The equation E = -∇V is referenced, confirming that the potential gradient points in the direction opposite to the electric field. Participant "ehild" confirms that the correct answer to the posed question is option C, which aligns with the established principles of electromagnetism.

PREREQUISITES
  • Understanding of electric fields and potential gradients
  • Familiarity with the concept of equipotential surfaces
  • Knowledge of vector calculus, specifically gradient notation
  • Basic grasp of electromagnetism principles
NEXT STEPS
  • Study the relationship between electric fields and potential gradients using E = -∇V
  • Explore the properties of equipotential surfaces in electrostatics
  • Learn about vector calculus applications in physics
  • Investigate common problems involving electric fields and potential differences
USEFUL FOR

Students in physics, particularly those studying electromagnetism, educators teaching electric field concepts, and anyone preparing for exams involving electric potential and gradients.

Yosty22
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Homework Statement



Attached.

Homework Equations



E=-∇V

The Attempt at a Solution



I think that the answer is C because it goes in the direction opposite the electric field and crosses through the most equipotential surfaces. Any confirmation or denial would be great.
Thank you.
 

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Just in case it is hard to look at, I rotated the attachment to make it easier.
 

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Yosty22 said:

Homework Statement



Attached.


I think that the answer is C because it goes in the direction opposite the electric field and crosses through the most equipotential surfaces. Any confirmation or denial would be great.
Thank you.

Yes, it is C.


ehild
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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