- #31
AdityaDev
- 527
- 33
That is what we want. Now the potential difference across the resistors will be different.Faris Shajahan said:
Measuring resistance using potentiometer
- Thread starter AdityaDev
- Start date
Click For Summary
Homework Help Overview
The discussion revolves around measuring resistance using a potentiometer, focusing on the relationship between current, potential difference, and resistance in a circuit. Participants explore the implications of varying resistances and the balancing lengths in the context of the potentiometer's operation.
Discussion Character
- Exploratory, Conceptual clarification, Assumption checking
Approaches and Questions Raised
- Participants question why the current is considered the same when resistances are varied, and how this affects the potential difference across the resistors. There are attempts to clarify the relationship between balancing lengths and the corresponding voltages, as well as discussions on internal resistance and its impact on measurements.
Discussion Status
The discussion is active, with various interpretations being explored regarding the current and voltage at the balance point. Some participants offer insights based on their experiences, while others express confusion and seek clarification on the concepts presented.
Contextual Notes
There are mentions of differing interpretations of textbook answers and the role of internal resistance in the measurements. Participants also note the challenge of applying theoretical concepts to practical scenarios, particularly in the context of homework constraints.
- #32
andrevdh
- 2,126
- 116
Usually this experiment is done with the resistors connected in series to the cell, in which case the
current will be the same through both resistors.
For this particular setup I can only reduce it to two unknowns, the resistance X, and the internal resistance of the cell.
current will be the same through both resistors.
For this particular setup I can only reduce it to two unknowns, the resistance X, and the internal resistance of the cell.
- #33
Faris Shajahan
- 29
- 4
AdityaDev said:
Yes, it will be different but still it would be impossible for us to calculate the value of ##X## as we don't have the value of ##r## given in the question.
Instead if they say there is a rheostat in series with ε in order to maintain constant current in both the cases, then we can calculate ##X## as
##X=R\frac{l_2}{l_1}##
Similar threads
- · Replies 4 ·
- · Replies 4 ·
- · Replies 13 ·
- · Replies 7 ·
- · Replies 2 ·
- · Replies 8 ·
- · Replies 14 ·