AdityaDev
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That is what we want. Now the potential difference across the resistors will be different.Faris Shajahan said:
Measuring resistance using potentiometer
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andrevdh
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Usually this experiment is done with the resistors connected in series to the cell, in which case the
current will be the same through both resistors.
For this particular setup I can only reduce it to two unknowns, the resistance X, and the internal resistance of the cell.
current will be the same through both resistors.
For this particular setup I can only reduce it to two unknowns, the resistance X, and the internal resistance of the cell.
Faris Shajahan
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AdityaDev said:
Yes, it will be different but still it would be impossible for us to calculate the value of ##X## as we don't have the value of ##r## given in the question.
Instead if they say there is a rheostat in series with ε in order to maintain constant current in both the cases, then we can calculate ##X## as
##X=R\frac{l_2}{l_1}##