This was a diagram, so I will describe it as accurately as possible.
12 Volts go through one 2 Ohm resistor which then proceeds through a set of resistors in parallel. One is 20 Ohms, the other two are 10 Ohms.
How much power is being dissipated by one of the 10 Ohm resistors?
V = IR
P = V * A
1/R(Parallel-Equivelant) = Sum(1/Rn)
The Attempt at a Solution
Can I calculate the Current after the first resistor using V = I * R ? If so, I know how to calculate the total resistance by using 1/R = Sum of (1/Rn). Would the resistance of one resistor just be 1/R = 1/10 --> R = 10?
THanks for any help