I have not been studying this, but I believe I know how to solve it based on this document: https://subjects.ee.unsw.edu.au/elec4614/Lecture%2010%20-%20Overlap%20in%201-phase%20circuits.pdf
See page 4, equation 10.3:
[itex]\cos(\alpha+\mu) = \cos \alpha - \underbrace{\frac{\omega L_s}{V_{max}}I_d}_{\text{constant}} \tag {10.3}[/itex]
We want to find the overlap angle [itex]\mu[/itex].
First we calculate the constant in the equation above, using [itex]\mu = 45^{\circ}[/itex] and [itex]\alpha = 0^{\circ}[/itex].
When we have obtained the value of the constant term, we use the same equation and solve for [itex]\mu[/itex] with [itex]\alpha = 45^{\circ}[/itex]
In my case this gave me [itex]\mu = 20.53^{\circ}[/itex].
As I said I have not been studying this, so it would be nice if someone could verify this.
Also, I would recommend you to understand how equation 10.3 is derived and not only insert numbers and use it.