Hello everyone I am a newbie to electrical engineering, I have this problem I've been strugling with, no textbook seems to cover this problem..(adsbygoogle = window.adsbygoogle || []).push({});

A three-phase, 440-V, generator delivers 5400W of active power through two recti-fies, A and B, into a three-phase, 230-V, line as shown in Figure 3.

The dc current through the inductor is 20A. If power loss in both rectifiers are negligible, calculate:

(a). Firing angle of the rectifier A;

(b). Firing angle of the rectifier (inverter) B.

This is my attempt ;

V out = 5400/ 20 = 270

For inductive load

VOUT = 1.35 × VLINE × cos α

Where ‘α’ is the firing angle of the rectifier.

Therefore,

cos α = V / 1.35 x Vline

α = 29

how does this seem? and how is the inverter's firing angle different?

**Physics Forums - The Fusion of Science and Community**

# Firing angle in rectifiers and inverters.

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

Have something to add?

- Similar discussions for: Firing angle in rectifiers and inverters.

Loading...

**Physics Forums - The Fusion of Science and Community**