- #1

jaus tail

- 615

- 48

## Homework Statement

## Homework Equations

I rms for triangular waveform = I(max)/ (1.732)

R = V/I

## The Attempt at a Solution

Since there is RLE load, current waveform is triangular. It is

Source current is

Average of I source. I used integration. Assumed Time period = 10 seconds. So T on = 5 seconds. (question says duty = 0.5)

So integrating I got average source current = 14.7 A

Average source voltage = 200 V

So input resistance = 200 / 14.7 = 13.6A

But I'm not able to get the first one. I get answer as 26.33 A But that is not even in the option.

I used formula square I(load) = square dc component (26.05) + square (rms of triangular waveform)

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