Power needed to keep conveyor belt moving at constant speed

In summary, the examiner report discusses the increase in kinetic energy of sand and points out that this cannot be the only power involved due to the implication of infinite acceleration for each grain of sand. This is because the assumption of each grain immediately going from rest to a certain velocity without passing through intermediate speeds goes against the laws of physics. The conversation concludes with the clarification that the reason for this is the instantaneous velocity change of a mass by a finite amount.
  • #1
Janiceleong26
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1. The problem statement, all variables and given/known
image.jpg


Homework Equations


P=Fv
K.E = 1/2 mv2

The Attempt at a Solution


This is the examiner report:
the kinetic energy of the sand does increase by 1/2 mv2 but this cannot be the only power involved (it would imply an infinite acceleration for every grain of sand landing on the belt)
Why infinite acceleration? Is it because the mass is too small?
 
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  • #2
Janiceleong26 said:
Why infinite acceleration? Is it because the mass is too small?
It is assuming that every grain of sand (each of which has a non-zero mass) immediately goes from rest to v without passing through any intermediate speeds. This would require an instantaneous velocity change of a mass by a finite amount, which would be breaking (or at best ignoring) the actual laws of physics.
 
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  • #3
gneill said:
It is assuming that every grain of sand (each of which has a non-zero mass) immediately goes from rest to v without passing through any intermediate speeds. This would require an instantaneous velocity change of a mass by a finite amount, which would be breaking (or at best ignoring) the actual laws of physics.
Oh I see, thanks very much
 

1. How is power calculated for a conveyor belt?

The power needed to keep a conveyor belt moving at constant speed can be calculated using the formula P = (T x v) / 1000, where P is power (kW), T is the tension (N), and v is the belt speed (m/s). This formula takes into account the weight of the load on the belt and the frictional forces.

2. What factors affect the power needed for a conveyor belt?

The power needed to keep a conveyor belt moving at constant speed can be affected by several factors such as the weight of the load on the belt, the frictional forces, the length and width of the belt, and the speed at which the belt is moving. Additionally, the incline or decline of the conveyor, as well as any changes in elevation, can also impact the power needed.

3. How does the load on the conveyor belt affect the power needed?

The weight of the load on the conveyor belt is a significant factor in determining the power needed to keep the belt moving at a constant speed. The heavier the load, the more power will be required to overcome the force of gravity and the frictional forces between the belt and its rollers.

4. Is it more efficient to run a conveyor belt at a higher or lower speed?

The most efficient speed for a conveyor belt will depend on the specific application, but generally speaking, a lower speed will require less power to maintain. However, a higher speed may be necessary to meet production demands or to move heavier loads.

5. How can the power needed for a conveyor belt be reduced?

There are several ways to reduce the power needed for a conveyor belt, including using a more efficient motor, reducing the weight of the load, decreasing the length or width of the belt, and minimizing frictional forces by properly maintaining the belt and its rollers. Additionally, implementing energy-saving measures such as using regenerative braking or variable speed drives can also help reduce power consumption.

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