Power needed to push an object vertical at constant velocity

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Homework Help Overview

The problem involves calculating the minimum power required for a motor to raise a ride at a theme park to a height of 39.6 meters in 10 seconds while maintaining a constant velocity. The subject area includes concepts from mechanics, specifically relating to forces, power, and energy.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate power using changes in kinetic energy and work done against gravity, but expresses confusion over the results. Some participants suggest using the relationship between power, force, and velocity, questioning the calculations of force and the implications of constant velocity.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been offered regarding the relationship between force and power, but there is no explicit consensus on the correct approach or calculations yet.

Contextual Notes

Participants are considering the implications of constant velocity, which suggests that acceleration is zero, and are discussing the forces acting on the ride, including gravity and the force from the motor. There is a focus on the assumptions made regarding friction and the forces involved.

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Homework Statement



Stuntman's Freefall, a ride at Six Flags Great Adventure in NewJersey, stands 39.6 meters high. Ignoring the force of friction, what is the minimum power rating of the motor that raises the 1.20×105kg ride from the ground to the top in 10.0 seconds at a constant velocity?

Homework Equations



Constant Velocity = 39.6 / 10 = 3.96m/s
1.20×105 = 120000.0 kg

The Attempt at a Solution



I've tried it two ways now, but clearly neither of them worked.

First way:

\DeltaKE = \frac{1}{2} * (1.20×105) * (3.96)2
\DeltaKE = 940,896
W = \DeltaKE
W = 940,896

P = \frac{W}{t}
P = \frac{940896}{10}
P = 94089.6 watts

This was wrong... so I tried this way

2nd way:

Velocity = 3.96m/s
Acceleration = .396m/s2
\sumFy = (1.20×105) * .396m/s2
\sumFy = 47,520

W = F * \Deltay
W = 47250 * 39.6
W = 1,881, 792

P = \frac{W}{t}
P = \frac{1881792}{10}
P = 188179.2 wattsRan out of ideas. What am I missing here?
 
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Constant velocity means ΔKE = zero.

Try power P = Fv where F is the force supplied by the motor. Can you find F?
 
kuruman said:
Constant velocity means ΔKE = zero.

Try power P = Fv where F is the force supplied by the motor. Can you find F?

Then I end up with the same answer as my second try though. Unless I'm calculating Force wrong?

Velocity = 3.96m/s
Acceleration = .396m/s2
Fy = m*a
Fy = (1.20×105) * .396m/s2
Fy = 47,520

P = F * v
P = (47520)(3.96)
P = 188179.2 watts
 
You need to convert velocity to acceleration.
 
Chronos said:
You need to convert velocity to acceleration.
I am not sure what this means. If the velocity is constant, the acceleration is zero. Here, we are neglecting friction, so there are only two forces acting on the ride, the lifting mechanism and gravity. If the ride moves at constant velocity, what must the force of the lifting mechanism be equal to?
 
If sumF = 0 then a = 0. The only forces are gravity and the motor.
 
Correct-o. Can you figure out then what the force exerted by the motor is?
 

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