A motorcycle (mass of cycle plus rider = 232 kg) is traveling at a steady speed of 21 m/s. The force of air resistance acting on the cycle and rider is 205 N. Find the power necessary to sustain this speed if (a) the road is level and (b) the road is sloped upward at 29.2° with respect to the horizontal. I got through part a.. where P=Fv=205N * 21 m/s= 4305 W but I'm not sure how to handle the opposing force of the motorcycle's weight down the slope... I THINK you can find it with W= F * cos29.2 s = 232kg * 9.8 m/s^2 * cos29.2 * 21 (where 21=s given the velocity..ie distance per unit time?... or would it be 1/21 s in order to get rid of one of the 1/s) THEN with this amount.. would you add it to part a?.. do you have to reconsider the air resistance since the bike is no longer traveling along the horizontal? (so.. 205N * sin29.2(?.. not cos because force is in opp direction) *21 m/s).. anyway.. a bit confused.. any insight would be very appreciated I have to turn this in tonight. Thanks!