Power Required to Move Elevator Cab in NY Marriott Marquis

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    Elevator Power
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SUMMARY

The power required to move the elevator cab in the New York Marriott Marquis, which has a mass of 4,150 kg and a maximum load of 1,800 kg, is calculated using the formula P = F * v, where F is the force and v is the velocity. The correct calculation for power, considering the upward movement at a velocity of 3.57 m/s, reveals that the initial approach of using kinetic energy was flawed due to incorrect application of the formulas. The final power requirement is determined to be 5,057.5 kW, highlighting the importance of using the correct variables in power calculations.

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goluigi2196
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1. An elevator cab in the New York Marriott Marquis has a mass of 4.15 x 103 kg and can carry a maximum load of 1.80 x 103 kg. If the cab is moving upward at full load at 3.57 m/s, what power is required of the force moving the cab to maintain that in kilowatts?W=Work P=Power t=Time F=Force d=distance g=gravity K=Kinetic Energy

Homework Equations


P=W/Δt
W=ΔK

therefore...
P=(1/2mv2)/Δt

The Attempt at a Solution


P=(1/2(4150+1800)2)/3.57

it's 4150+1800 because full load is 1800 kg and the elevator is 4150 kg.

solve for P and you get 5057500 W or 5057.5 kW

it says I'm wrong. What did I do wrong?EDIT

wow. fail. i forgot that it is divided by time, not velocity -_-
 
Physics news on Phys.org
Hint: Another formula for power uses force and velocity.
 
It also didn't help that you squared the mass of the elevator cab and the payload in your original calculation.
 

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