Power Series ArcTan: Analyzing the Expansion & Convergence

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SUMMARY

The discussion focuses on the power series expansion of the function f(t) = 4/(1+t^2) and its integral G(x) = ∫ from 0 to x of f(t) dt. The first four nonzero terms of the power series for f(t) are established as 4 - 4t^2 + 4t^4 - 4t^6. For G(x), the power series can be derived by integrating the series term by term, leading to G(x) = 4arctan(x). The interval of convergence for G(x) is determined through analysis of the series expansion.

PREREQUISITES
  • Understanding of power series expansions
  • Knowledge of integration techniques, specifically term-by-term integration
  • Familiarity with the function Arctan and its derivative
  • Basic calculus concepts including limits and convergence
NEXT STEPS
  • Learn about power series convergence tests, such as the Ratio Test
  • Study the properties and applications of the Arctan function
  • Explore term-by-term integration of power series
  • Investigate the Taylor series expansion for common functions
USEFUL FOR

Students and educators in calculus, particularly those focusing on power series, integration techniques, and the properties of trigonometric functions. This discussion is beneficial for anyone looking to deepen their understanding of series expansions and convergence analysis.

sammiekurr
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Power Series ArcTan?

Homework Statement


Let f be the function given by f(t) = 4/(1+t^2) and G be the function given by G(x)= Integral from 0 to x of f(t)dt.
A) Find the first four nonzero terms and the general term for the power series expansion of f(t) about x=0.
B) Find the first four nonzero terms and the general term for the power series expansion of G(t) about x=0.
C) Find the interval of convergence of the power series in part (B). Show the analysis that leads to your conclusion.


Homework Equations


d/dtArctan(t)=1/(1+t^2)


The Attempt at a Solution


A) a=4, R=-t^2. f(t)=Sum from n=1 to infinity of 4 * (-1)^n * t^2n
First four terms: -4t^2 + 4t^4 - 4t^6 + 4t^8

B) Integral from 0 to x of 4/(1+t^2)dt = 4arctan(t) from 0 to x = 4arctan(x)

Now I don't know where to go from here. I don't know how to write the power series for the antiderivative of the original power series, since it is not in the standard form of a power series. Can anybody help?
 
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sammiekurr said:

Homework Statement


Let f be the function given by f(t) = 4/(1+t^2) and G be the function given by G(x)= Integral from 0 to x of f(t)dt.
A) Find the first four nonzero terms and the general term for the power series expansion of f(t) about x=0.
B) Find the first four nonzero terms and the general term for the power series expansion of G(t) about x=0.
C) Find the interval of convergence of the power series in part (B). Show the analysis that leads to your conclusion.


Homework Equations


d/dtArctan(t)=1/(1+t^2)


The Attempt at a Solution


A) a=4, R=-t^2. f(t)=Sum from n=1 to infinity of 4 * (-1)^n * t^2n
First four terms: -4t^2 + 4t^4 - 4t^6 + 4t^8
No. You have the formula right but when n= 0, 4(-1)^n t^2n is 4. The first four terms are 4- 4t^2+ 4t^4- 4t^6.

B) Integral from 0 to x of 4/(1+t^2)dt = 4arctan(t) from 0 to x = 4arctan(x)

Now I don't know where to go from here. I don't know how to write the power series for the antiderivative of the original power series, since it is not in the standard form of a power series. Can anybody help?
Why is it "not in the standard form of a power series"?

You have that [itex]4/(1+ t^2)= 4\sum_{n=0}^\infty (-1)^n t^{2n}[/itex] and can integrate "term by term".
 

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