the question is...

Determine the interval and radius of convergence of the power series below..

[tex]\sum\limits_{k=0}^\infty[/tex]k!(x-3)^k

i've already find the radius, r = 0

then..

c - r < x < c + r

3 - 0 < x < 3 + 0

hence, x = 3

when x = 3..

[tex]\sum\limits_{k=0}^\infty[/tex]k!(3-3)^k = 0

so.. the interval of convergence is 0

am i do it right?