- #1
naspek
- 181
- 0
hey there.. i hope u guys can help me..
the question is...
Determine the interval and radius of convergence of the power series below..
[tex]\sum\limits_{k=0}^\infty[/tex]k!(x-3)^k
i've already find the radius, r = 0
then..
c - r < x < c + r
3 - 0 < x < 3 + 0
hence, x = 3
when x = 3..
[tex]\sum\limits_{k=0}^\infty[/tex]k!(3-3)^k = 0
so.. the interval of convergence is 0
am i do it right?
the question is...
Determine the interval and radius of convergence of the power series below..
[tex]\sum\limits_{k=0}^\infty[/tex]k!(x-3)^k
i've already find the radius, r = 0
then..
c - r < x < c + r
3 - 0 < x < 3 + 0
hence, x = 3
when x = 3..
[tex]\sum\limits_{k=0}^\infty[/tex]k!(3-3)^k = 0
so.. the interval of convergence is 0
am i do it right?