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**1. Making appropriate use of resistor combination techniques, calculate i3 in the circuit of Fig. 3.84 and the power provided to the circuit by the single current source.**

**2. Connected in Parallel and Series. Ohm's Law. KCL/KVL**

**3. I honestly am just guessing how to do this one:**

The 3 ohms and 5 ohms resistors are in parallel to one another, so combining their resistance should give 1.875 ohms. The 3 ohms and the 9 ohms resistors too are in parallel, so they should give a total resistance of 2.25 ohms, which can be added to the 3 ohms and 5 ohms in the rightmost branch, to give 10.25 ohms. That leaves us with another pair of resistors in parallel, the 3 ohms and the 6 ohms, which when combined give us 2 ohms.

Now we have two resistors in parallel. The resistor of 1.875 ohms and the resistor of 12.25 ohms. This gives a total resistance of 1.626 ohms.

This can be used to find what I3 is:

1 - 1.626(I3) = 0

I3 = 0.615 A

Now that we know what I3 is, we can calculate the power source using the current.

The 3 ohms and 5 ohms resistors are in parallel to one another, so combining their resistance should give 1.875 ohms. The 3 ohms and the 9 ohms resistors too are in parallel, so they should give a total resistance of 2.25 ohms, which can be added to the 3 ohms and 5 ohms in the rightmost branch, to give 10.25 ohms. That leaves us with another pair of resistors in parallel, the 3 ohms and the 6 ohms, which when combined give us 2 ohms.

Now we have two resistors in parallel. The resistor of 1.875 ohms and the resistor of 12.25 ohms. This gives a total resistance of 1.626 ohms.

This can be used to find what I3 is:

1 - 1.626(I3) = 0

I3 = 0.615 A

Now that we know what I3 is, we can calculate the power source using the current.