# Power Source = I3 x 12 VPower Source = 7.38 W

• Mosaness
In summary, a summary of the conversation is that resistor combination techniques can be used to calculate the power provided to a circuit by a current source, Ohm's Law can be applied to calculate the current through a circuit, and KCL can be used to find the voltage in a circuit.

#### Mosaness

1. Making appropriate use of resistor combination techniques, calculate i3 in the circuit of Fig. 3.84 and the power provided to the circuit by the single current source.

2. Connected in Parallel and Series. Ohm's Law. KCL/KVL

3. I honestly am just guessing how to do this one:

The 3 ohms and 5 ohms resistors are in parallel to one another, so combining their resistance should give 1.875 ohms. The 3 ohms and the 9 ohms resistors too are in parallel, so they should give a total resistance of 2.25 ohms, which can be added to the 3 ohms and 5 ohms in the rightmost branch, to give 10.25 ohms. That leaves us with another pair of resistors in parallel, the 3 ohms and the 6 ohms, which when combined give us 2 ohms.

Now we have two resistors in parallel. The resistor of 1.875 ohms and the resistor of 12.25 ohms. This gives a total resistance of 1.626 ohms.

This can be used to find what I3 is:

1 - 1.626(I3) = 0

I3 = 0.615 A

Now that we know what I3 is, we can calculate the power source using the current.

#### Attachments

• 3.84.png
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Assuming that you're analysis of resistors is correct (seemed like you had the right approach but I didn't double check), the equation you stated isn't correct because this is a current source not a voltage and your equation is mixing the two.
This problem is to make sure you understand KCL.
I_s = I3 +I2 + I1 = v/R_t = v/(R3+R2+R1)
I_s = 1A and voltage is the same to all branches.

I'd start with finding the equivalent resistance branch(es) and the total resistance. Calculate voltage then go about finding branch currents.

Mosaness said:
1. Making appropriate use of resistor combination techniques, calculate i3 in the circuit of Fig. 3.84 and the power provided to the circuit by the single current source.

2. Connected in Parallel and Series. Ohm's Law. KCL/KVL

3. I honestly am just guessing how to do this one:

The 3 ohms and 5 ohms resistors are in parallel to one another, so combining their resistance should give 1.875 ohms. The 3 ohms and the 9 ohms resistors too are in parallel, so they should give a total resistance of 2.25 ohms, which can be added to the 3 ohms and 5 ohms in the rightmost branch, to give 10.25 ohms. That leaves us with another pair of resistors in parallel, the 3 ohms and the 6 ohms, which when combined give us 2 ohms.

Now we have two resistors in parallel. The resistor of 1.875 ohms and the resistor of 12.25 ohms. This gives a total resistance of 1.626 ohms.

This can be used to find what I3 is:

1 - 1.626(I3) = 0

I3 = 0.615 A

Now that we know what I3 is, we can calculate the power source using the current.
Your equation (in red) says that 1A = 1.626 (Ω) * I3 (A) , which is wrong.
The voltage is Vx=3i3. You have 1-i3 current flowing through the parallel resultant of the 12.25 Ω resistor and 5 Ω resistor, Rp. Rp(1-i3)=Vx.

ehild

## What does "Power Source = I3 x 12 V" mean?

This statement indicates that the power source is equal to the current (I) cubed multiplied by 12 volts. This is known as the power formula: P = I^3 * V, where P is power, I is current, and V is voltage.

## How is power calculated from the given information?

The power can be calculated by plugging in the values for current and voltage into the power formula: P = I^3 * V. In this case, the power would be equal to 7.38 watts.

## What is the significance of "12 V" in the power source?

The 12 V refers to the voltage of the power source. Voltage is a measure of the electric potential difference between two points and is typically measured in volts (V). In this case, the power source has a voltage of 12 V.

## What is the unit of measurement for "7.38 W"?

The unit of measurement for 7.38 W is watts (W), which is the standard unit for power. Watts measure the rate at which energy is transferred or used.

## How does "I3" affect the overall power of the source?

The "I3" in the power formula represents the current (I) cubed, which means that it has a significant impact on the overall power of the source. As the current increases, the power of the source will also increase exponentially, as it is raised to the third power.