How Much Power is Needed to Lift 89 Skiers Up a Slope?

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SUMMARY

The discussion focuses on calculating the motor power required to lift 89 skiers up a 600 m slope inclined at 15° using a T-bar tow. The average mass of each skier is 65 kg, and the coefficient of kinetic friction is 0.06. Key formulas used include work (w = F * d) and power (P = F * v). The normal force was calculated to be 615.923 N, and the frictional force was determined to be 36.955 N, leading to further inquiries about the work done by friction and other forces acting on the skiers.

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1. A T-bar tow is required to pull 89 skiers up a 600 m slope inclined at 15° above horizontal at a speed of 2.5 m/s. The coefficient of kinetic friction is 0.06. Find the motor power required if the mass of the average skier is 65 kg.




2. w=F*d
P=F*v




3. I found the normal force to be 615.923 N I then found the frictonal force to be 36.955N. Where do i go from here?
 
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If you know the frictional force, how much work does it do on the skier? Are there any other forces doing work on the skier?
 

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