Power, Torque, and Velocity in a Pulley System

Click For Summary
The discussion focuses on calculating the tension in the cord attached to two books and the moment of inertia of a pulley in a frictionless system. The first book has a mass of 1.99 kg on a horizontal surface, while the second book, with a mass of 2.97 kg, hangs vertically. The system is released from rest, and the books move a distance of 1.20 m in 0.790 seconds, allowing for the calculation of acceleration. Key equations include F=ma, Torque= Iα, and I=mR², which relate the forces acting on the books and the pulley. The tension in the cable varies when the system is in motion, and understanding the effects of the pulley's inertia is crucial for solving the problem.
David112234
Messages
105
Reaction score
3

Homework Statement


A textbook of mass 1.99 kg rests on a frictionless, horizontal surface. A cord attached to the book passes over a pulley whose diameter is 0.150 m , to a hanging book with mass 2.97 kg . The system is released from rest, and the books are observed to move a distance 1.20 m over a time interval of 0.790 s .

A.What is the tension in the part of the cord attached to the textbook?
B.What is the tension in the part of the cord attached to the book?
C.What is the moment of inertia of the pulley about its rotation axis?

2. Homework Equations

F=ma
Torque= Iα
a=Rα
I=mR2

The Attempt at a Solution


book.jpg

Forces on book 1 (on top/textbook)

mg and Normal force cancel each other so the only force is to the right, Tension

t1=m1a

Forces on book 2 (hanging one)

-t2 + m2g= -m2a

Forces on wheel pulley

The string will create a torque in the clockwise direction

T = Iα
a = Rα
a/R = α

T = I (a/R)

I am stumped as what to do, I can find the t1 by using the second equation and solving for a in terms of t2 and plugging it back into the first one but then I would have another unknown variable.
 
Physics news on Phys.org
Before the books start to move the tension in the cable is the hanging mass X the acceleration of gravity. The tension in the cable is the same at all points in the cable when the books are at rest. Assume that the books accelerate at a constant rate. The distance traveled is equal to 1/2 the acceleration times the square of the elapsed time. Rearrange terms to find the acceleration. Compare that acceleration to the acceleration due to the masses and forces involved. Acceleration equals force divided by mass. Any difference between the two acceleration rates could be assumed to be the effects of the inertia of the pulley. That's as far as you can go without knowing either the mass or the radius of the pulley (or both mass and radius).

Once things start moving the forces on the cable will be different on each side of the pulley. You can calculate that using the observed acceleration and the mass of the books.

That should get you started.
 
If have close pipe system with water inside pressurized at P1= 200 000Pa absolute, density 1000kg/m3, wider pipe diameter=2cm, contraction pipe diameter=1.49cm, that is contraction area ratio A1/A2=1.8 a) If water is stationary(pump OFF) and if I drill a hole anywhere at pipe, water will leak out, because pressure(200kPa) inside is higher than atmospheric pressure (101 325Pa). b)If I turn on pump and water start flowing with with v1=10m/s in A1 wider section, from Bernoulli equation I...

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 34 ·
2
Replies
34
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 30 ·
2
Replies
30
Views
3K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 10 ·
Replies
10
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
8
Views
13K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K