Power/Work-Energy HW: Find Tension in Ski Boat Tow Rope

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Homework Help Overview

The discussion revolves around calculating the tension in a tow rope of a ski boat based on power and speed. The context involves understanding the relationship between power, force, and speed in a physics problem related to work and energy.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the application of the power equation P = Fv and question the calculations related to the power needed to pull both the boat and the skier. There are attempts to clarify the power differences and how they relate to the forces involved.

Discussion Status

The discussion includes various attempts to derive the correct force from the given power values. Some participants provide equations and question the arithmetic involved in the calculations. There is no clear consensus on the final answer, but several lines of reasoning are being explored.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the information they can use or the methods they can apply. There are indications of confusion regarding significant figures and the proper interpretation of power values.

Parzival
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Homework Statement


The motor of a ski boat generates an average power of 7.50 * 10^4 W when the boat is moving at a constant speed of 12 m/s. When the boat is pulling the skier at the same speed, the engine must generate an average power of 8.30 * 10^4 W. What is the tension in the tow rope that is pulling on the skier?


Homework Equations


Average power = force * average speed
Average power = change in energy/time
Average power = Work/time


The Attempt at a Solution



I tried setting up an equation:

8.30 * 10^4 W = F*12 m/s
F = 83,000/12 N

= 7 * 10^3 N which is wrong.
 
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Parzival said:
I tried setting up an equation:

8.30 * 10^4 W = F*12 m/s
F = 83,000/12 N

= 7 * 10^3 N which is wrong.


The motor needs to move both the boat and the skier. The boat is pulled with 7.50 * 10^4 W. What is the power of the force that moves the skier then?

ehild
 
Another useful equation that would work in your case is

P=Fv

This comes from the fact that

P = ΔW/Δt = FΔx/Δt = Fv
 
Last edited:
ehild said:
The motor needs to move both the boat and the skier. The boat is pulled with 7.50 * 10^4 W. What is the power of the force that moves the skier then?

ehild

Is it 83000 - 75000 = 1.2 * 10^4?
 
Parzival said:
Is it 83000 - 75000 = 1.2 * 10^4?

It is 83000 - 75000, but not 1.2 * 10^4. Check the subtraction.

ehild
 
ehild said:
It is 83000 - 75000, but not 1.2 * 10^4. Check the subtraction.

ehild

Fail. So 8.0 * 10^4?
 
harts said:
Another useful equation that would work in your case is

P=Fv

This comes from the fact that

P = ΔW/Δt = FΔx/Δt = Fv

interesting derivation
 
Its not 8*10^4 either. That's, 80,000.

And.. thanks?
 
harts said:
Its not 8*10^4 either. That's, 80,000.

And.. thanks?


Fail. 8*10^3. Why thanks?
 
  • #10
The skier is pulled at v=12 m/s speed by 8000 W power. What is the pulling force then?

ehild
 
  • #11
deleting my post
 
  • #12
ehild said:
The skier is pulled at v=12 m/s speed by 8000 W power. What is the pulling force then?

ehild


So: 8000/12 N is the answer. Significant digits yield 6.7*10^2, which is correct!
 

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