Pressure and Bernoulli + Continuity

[physgrl]

Homework Statement

Water flows through a horizontal tapered pipe. At the wide end its speed is 4.0 m/s and at the narrow end it is 5.0 m/s. The pressure in the wide pipe is 2.5 x 10^5 Pa. What is the pressure in the narrow pipe?

a. 2.5 x 10^2 Pa
b. 3.4 x 10^3 Pa
c. 4.5 x 10^3 Pa
d. 2.3 x 10^5 Pa
e. 8.0 x 10^5 Pa

Homework Equations

P1+1/2*ρ*v1² = P2+1/2*ρ*v2²
A1*v1=A2*v2

The Attempt at a Solution

1-wide
2-narrow

P1+1/2*ρ*v1² = P2+1/2*ρ*v2²

2.5 x 10^5 Pa + 1/2*1000kg/m³*(4m/s)²=P2 + 1/2*1000kg/m³*(5m/s)²

2.5 x 10^5 Pa + 1/2*1000kg/m³*(4m/s)²- 1/2*1000kg/m³*(5m/s)²=P

2.5 x 10^5 Pa + 1/2*1000kg/m³*[(4m/s)²-(5m/s)²]=P

2.455x10^5 Pa=P

the answer is not in the options :s can someone tell me what i did wrong?

 

[LawrenceC]

I agree with your answer. Looks like an error in supplied answer.

 

[physgrl]

thanks! :)