Pressure at Bottom of Flask: Liq. 1, 2 & 3

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SUMMARY

The pressure at the bottom of a flask containing three distinct liquids can be calculated using the hydrostatic pressure formula, P = ρgh, for each liquid layer. In this case, Liquid 1 (density = 6660 kg/m³, depth = 0.708 m), Liquid 2 (density = 4995 kg/m³, depth = 0.90 m), and Liquid 3 (density = 1369 kg/m³, depth = 0.685 m) must be considered. The total pressure at the bottom of the flask is the sum of the pressures from each liquid layer plus atmospheric pressure, which is typically 101325 Pa. Therefore, the correct approach is to calculate the pressure from each liquid and then add atmospheric pressure to the final total.

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Liquid 1 with density = 6660 kg/m^3 is poured into cylinder to depth d1 = 70.8 cm; Liq. 2 with density 4995 kg/m^3 is poured on top to a depth of 90cm; and then liquid 3 (density of 1369 kg/m^3) is poured on top of liquid 2 to a depth of 68.5cm). Assuming none of the liquids mix at all what is the pressure at bottom of flask?

I used ρgh for each and added but this is wrong. Should I add the atmospheric pressure to the total?
 
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Any help would be much appreciated..please?
 
Should I add the atmospheric pressure to each calculation or to the total (after adding each (densityxgxh calculation)?
 

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