Pressure drag acting on a sphere

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SUMMARY

The pressure drag acting on a sphere can be expressed as 2πμaU, where U is the fluid speed, a is the sphere's radius, and μ is the viscosity. To derive this formula, one must integrate the pressure distribution around the sphere's surface, taking into account the normal vector directionality of the pressure forces. The pressure at a position r is defined by the equation P-P0 = -1.5μUacos(Θ)/r². A common mistake is to neglect the vectorial nature of the forces, leading to incorrect results such as zero when integrating over the surface.

PREREQUISITES
  • Understanding of fluid dynamics principles
  • Familiarity with vector calculus
  • Knowledge of pressure distribution equations
  • Basic concepts of drag force in fluid mechanics
NEXT STEPS
  • Study vector integration techniques in fluid dynamics
  • Learn about the derivation of drag equations for various shapes
  • Explore the role of viscosity in fluid flow around objects
  • Investigate computational fluid dynamics (CFD) simulations for drag analysis
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Students and professionals in fluid mechanics, engineers working on aerodynamic designs, and anyone interested in understanding pressure drag on spherical objects.

Zar139
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Homework Statement


I am trying to show that the pressure drag acting on a sphere is 2πμaU by integrating around the surface of the sphere where U is the speed of the fluid the sphere is in, a is its radius, and μ is the viscosity.

Homework Equations


The pressure at a given position r can be written as:
P-P0 = -1.5μUacos(Θ)/r2

The Attempt at a Solution


I have tried integrating the above equation for Θ from 0 to 2π over the surface of the sphere but my answer is 0 which is clearly not the correct answer. I feel like this should be a fairly easy integration but I do not know how else to go about it. Any suggestions would be greatly appreciated.

Thank you!
 
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Zar139 said:

Homework Statement


I am trying to show that the pressure drag acting on a sphere is 2πμaU by integrating around the surface of the sphere where U is the speed of the fluid the sphere is in, a is its radius, and μ is the viscosity.

Homework Equations


The pressure at a given position r can be written as:
P-P0 = -1.5μUacos(Θ)/r2

The Attempt at a Solution


I have tried integrating the above equation for Θ from 0 to 2π over the surface of the sphere but my answer is 0 which is clearly not the correct answer. I feel like this should be a fairly easy integration but I do not know how else to go about it. Any suggestions would be greatly appreciated.

Thank you!
The pressure acts normal to the surface of the sphere at all locations. So, you have to include this directionality in your determination of the drag force.
 
Does this mean that I should multiply the area element dS by the unit normal vector?
 
Zar139 said:
Does this mean that I should multiply the area element dS by the unit normal vector?
You definitely have to integrate the forces vectoriallly. How you do this depends on how you want to approach it.
 

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