# Pressure on sides and ends of pool, given the pools dimensions and depth

1. Nov 1, 2009

### denxnis

1. The problem statement, all variables and given/known data
A swimming pool has dimensions 34.0 m 9.0 m and a flat bottom. When the pool is filled to a depth of 2.30 m with fresh water, what is the force caused by the water on the bottom?

I have the answer to this which is 6.90 x 10^6, however I cannot figure out the pressure on the sides or ends.

2. Relevant equations
Pressure on bottom = water density X gravity x area

3. The attempt at a solution
I understand the water depth has to play into this somehow but I cannot figure out how...
I attempted 9.80 x 2 x 9 = 176.4 kN
and
9.80 x 2 x 34 = 666.4 kN

These were incorrect

Last edited: Nov 1, 2009
2. Nov 1, 2009

Check it.

3. Nov 1, 2009

### denxnis

Apologies,
ρ = density - P = pressure - F = force - b = bottom of pool -
z = area of pool
Pb = ρgz
Fb = PbA

4. Nov 1, 2009

### rl.bhat

z is the depth of the water. Now find the pressure at the bottom Pb and then Fb