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Pressure on sides and ends of pool, given the pools dimensions and depth

  1. Nov 1, 2009 #1
    1. The problem statement, all variables and given/known data
    A swimming pool has dimensions 34.0 m 9.0 m and a flat bottom. When the pool is filled to a depth of 2.30 m with fresh water, what is the force caused by the water on the bottom?

    I have the answer to this which is 6.90 x 10^6, however I cannot figure out the pressure on the sides or ends.

    2. Relevant equations
    Pressure on bottom = water density X gravity x area

    3. The attempt at a solution
    I understand the water depth has to play into this somehow but I cannot figure out how...
    I attempted 9.80 x 2 x 9 = 176.4 kN
    9.80 x 2 x 34 = 666.4 kN

    These were incorrect
    Last edited: Nov 1, 2009
  2. jcsd
  3. Nov 1, 2009 #2


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    Homework Helper

    Your relevant equation is wrong.
    Check it.
  4. Nov 1, 2009 #3
    ρ = density - P = pressure - F = force - b = bottom of pool -
    z = area of pool
    Pb = ρgz
    Fb = PbA
  5. Nov 1, 2009 #4


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    Homework Helper

    z is the depth of the water. Now find the pressure at the bottom Pb and then Fb
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