Pressure relief from 15,000 psi to 0

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Discussion Overview

The discussion revolves around calculating the additional length of a tube required to relieve pressure from 15,000 psi to 0 psi using water as a medium. The context includes considerations of hydraulic systems and the properties of water under high pressure.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant queries the need for tube size and valve throat diameter, suggesting that water's incompressibility means any opening will relieve pressure.
  • Another participant provides an example involving a hydraulic cylinder, seeking to determine the travel length of the piston needed to achieve 0 psi.
  • Some participants argue that the original question may not make sense as posed, emphasizing that water is generally treated as incompressible.
  • One participant introduces the concept of water's compressibility at high pressures, citing specific values and suggesting that at 15,000 psi, the assumption of incompressibility may not hold, estimating a volume decrease of about 5%.
  • A later reply notes that if the valve is a pressure relief valve, a pressure differential is necessary for operation, implying that pressure may not reach 0 kPa without venting to the atmosphere.

Areas of Agreement / Disagreement

Participants express differing views on the relevance of water's incompressibility at high pressures, with some asserting that the question lacks clarity while others explore the implications of compressibility. The discussion remains unresolved regarding the calculation of the additional tube length needed.

Contextual Notes

There are limitations regarding the assumptions made about water's compressibility at high pressures, and the discussion does not resolve the mathematical steps necessary to determine the additional tube length.

pankajmala
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If, I have a 2.5" dia X 60 inches tube, at a internal pressure of 15,000 psi. If the valve is opened (orifice opening of 3/4" Dia), what will be the ( same dia) additonal length of tube that will be needed to relieve the pressure from 15,000 psi to 0, Using water as a medium at 75 deg F. The goal is to bring down the presure to 0 before it is existed out of the equipment.

if there are any other suggestions , I am open to it.

PP
 
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I'm missing something in your question.
Water is essentially incompressible, so any opening will relieve the pressure.
Tube size and valve throat diameter are not really needed afaik, but there may be more to the question than what you have given.
 
Thanks for replying so fast, example: take a hydraulic cylinder. when I compress the piston to a length of 60" ( ID of the cylinder is 2.5" dia ) I reach a pressure of 15,000psi. Now , when I let go the piston to retrieve back , assuming I have enough length for the piston to travel. what will be the length of the cylinder the piston has to travel so that the pressure in the cylinder will be 0 ?.
 
As etudiant said, water is essentially incompressible, this question therefore doesn't make much sense as it is stated. If you were talking about air (or any other compressible medium) the question would make sense.
 
pankajmala said:
If, I have a 2.5" dia X 60 inches tube, at a internal pressure of 15,000 psi. If the valve is opened (orifice opening of 3/4" Dia), what will be the ( same dia) additonal length of tube that will be needed to relieve the pressure from 15,000 psi to 0, Using water as a medium at 75 deg F. The goal is to bring down the presure to 0 before it is existed out of the equipment.

Others have pointed out that water is usually approximated as being incompressible. But at 15,000 psi this may no longer be an adequate approximation.

Per Wikipedia...

"The compressibility of water is a function of pressure and temperature. At 0 °C, at the limit of zero pressure, the compressibility is 5.1×10−10 Pa−1. At the zero-pressure limit, the compressibility reaches a minimum of 4.4×10−10 Pa−1 around 45 °C before increasing again with increasing temperature. As the pressure is increased, the compressibility decreases, being 3.9×10−10 Pa−1 at 0 °C and 100 MPa.

The bulk modulus of water is 2.2 GPa. The low compressibility of non-gases, and of water in particular, leads to their often being assumed as incompressible. The low compressibility of water means that even in the deep oceans at 4 km depth, where pressures are 40 MPa, there is only a 1.8% decrease in volume."

40 MPa is about 400 atmospheres. You are talking about 1000 atmospheres. So that's more like a five percent decrease in volume. Five percent of 60 inches is 3 inches.

That's more than I'd expected.
 
If the valve in question is a pressure relief valve they usually require a presssure differential to operate so the pressure will not reach 0kPa without a vent to atmosphere on the outlet.
 

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