Let p be a prime number.(adsbygoogle = window.adsbygoogle || []).push({});

Let A be an integer divisible by p but B be an integer not be divisible by p.

Let A/B be an integer.

How do I prove that A/B is divisible by p?

This sounds like a simple question but I just can't get it. I'm doing it in relation to proving Fermat's little theorem. (a^p = a mod p for all integers a) I'm trying to understand why the binomial coefficients in the binomial expansion of (1+a)^n are all divisible by p (=0 mod p) for all the terms with powers [1, p-1].

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# Prime number dividing fractions.

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