How to Calculate Principal Stresses in a Stressed Component?

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SUMMARY

The discussion focuses on calculating principal stresses in a stressed component using the given stress values: sigma(x) = 220MPa, sigma(y) = -95MPa, and shear = 60MPa. The primary formula for determining principal stresses is derived from the general formula for plane stresses. Additionally, the angle of maximum stresses relative to sigma(x) can be calculated using the equation tg(2A) = Txy / (Nx - Ny), where A represents the angle of the principal stress, Nx and Ny are normal stresses, and Txy is the shear stress.

PREREQUISITES
  • Understanding of stress components: normal stress and shear stress
  • Familiarity with the general formula for plane stresses
  • Knowledge of 2D Mohr Circle for stress transformation
  • Basic trigonometry, specifically tangent functions
NEXT STEPS
  • Study the derivation and application of the general formula for plane stresses
  • Learn how to construct and interpret the 2D Mohr Circle
  • Practice calculating principal stresses using various stress states
  • Explore advanced topics in stress analysis, such as stress concentration factors
USEFUL FOR

Mechanical engineers, structural analysts, and students studying stress analysis in materials will benefit from this discussion.

cabellos
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Principal stresses help please?

I am looking through past paper examinations and have come a across a question:

At a certain critical point in a stressed component, calculations show that the stresses are sigma(x) = 220MPa sigma(y) = -95MPa and shear = 60MPa

Find the maximum and minimum direct stresses (principal stresses) in the component at that point?

How do i go about this problem?

Thankyou.
 
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Well, do you know any related formulae? To be more specific, there is exactly one formula you need to apply.
 
Ah yes i think I have a solution to this problem now using the general formula for plane stresses.

There is a second part to the question where it now asks to find the angle which the maximum stresses make with the direction sigma(x)?

Does this involve the 2D Mohr Circle?
 
cabellos said:
Ah yes i think I have a solution to this problem now using the general formula for plane stresses.

There is a second part to the question where it now asks to find the angle which the maximum stresses make with the direction sigma(x)?

Does this involve the 2D Mohr Circle?

You can simply use tg(2A) = Txy / (Nx - Ny), where A is the angle of the principal stress, Nx and Ny are normal stresses and Txy is the shear stress.

Have on mind that tg2(A + Pi/2) = tg(2A).
 

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