2 objects are connected by a light string passing over a light frictionless pulley. The 5kg object is released from rest. Using the principle of conservation of energy, (a) determine the speed of the 3kg object just as the 5kg object hits the ground
The picture shows the 3kg object at rest connected by a string to a pulley vertically....and the 5kg object hangin from a string from the pulley with 4m height between the ground and the 5kg object.
4.43m/s is answer to a
The Attempt at a Solution
.5mv^2 + g(mf-mi)y=.5(5)v^2 + (-9.8)(2)(4)===>