Principle Quantum Number - Transition

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SUMMARY

The transition from the state [4,3,0,1/2] to [4,2,1,-1/2] is allowed based on the selection rules for quantum transitions. The calculations show that Δn = 0, Δl = 1, and Δml = -1, which satisfy the criteria for allowed transitions. However, since Δn = 0, there is no energy change associated with this transition, indicating that the electron does not emit or absorb a photon during this process. The discussion highlights the nuances of energy levels in hydrogen atoms and the implications of the Bohr model versus actual quantum mechanics.

PREREQUISITES
  • Understanding of quantum mechanics principles
  • Familiarity with the Bohr model of the hydrogen atom
  • Knowledge of selection rules for quantum transitions
  • Basic concepts of energy levels in atomic physics
NEXT STEPS
  • Study the implications of Δn = 0 in quantum transitions
  • Research the differences between the Bohr model and modern quantum mechanics
  • Explore the concept of energy levels for different l-states within the same n
  • Learn about photon absorption and emission processes in quantum systems
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Students of quantum mechanics, physics educators, and anyone interested in atomic transitions and energy level configurations in hydrogen atoms.

cpmiller
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Homework Statement


Is the following transition allowed?

[4,3,0,1/2] -> [4,2,1, -1/2]

If so, find the energy involved and whether the photon is absorbed or emitted for the hydrogen atom.

Homework Equations



Selection rules for allowed transitions:
\Deltan = anything
\Deltal =\pm1
\Deltaml = 0 or \pm1

The Attempt at a Solution



\Delta n = 4-4 = 0
\Delta l = 3-2 = 1
\Deltaml = 0-1= -1

So all of the transitions are allowed, but it doesn't quite make sense to me.

There is no energy involved, because \Delta n = 0, which means that this electron just suddenly spontaneously decided to be in a different configuration, can it do that?

(I also checked and it looks like both of the states are allowed...)

Can it do that, am I missing something?

Thanks for your help!
 
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Your reasoning makes sense, the transition does appear to be allowed.

While the Bohr theory predicts the same energies, in reality the energies will be slightly different. Does your textbook or lecture notes say anything about energies of different l-states within the same n?
 

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