Probabilities for orthonormal wavefunctions

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Homework Help Overview

The discussion revolves around calculating probabilities associated with orthonormal wavefunctions in quantum mechanics, specifically focusing on the observable operator and its eigenvalues.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore how to express the probabilities of obtaining specific eigenvalues in terms of the wavefunctions and the observable operator. There is a discussion about the relationship between eigenvalues, eigenstates, and the state of the system.

Discussion Status

Some participants have provided hints and guidance on how to approach the problem, particularly regarding the use of the identity operator and its relation to the wavefunctions. There is an acknowledgment of the foundational principles of quantum mechanics that may be relevant to the discussion.

Contextual Notes

There is a mention of specific resources, such as Griffiths' text, which may contain relevant equations and principles that are being referenced in the discussion.

kac9
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Ok I have two orthonormal wavefunctions of a system, \psi 1 and \psi 2 and \widehat{A} is an observable such that

\widehat{A} |\phi _{n} > = a_{n} |\phi _{n} >

for eigenvalues a sub n

what are the probabilities p1(a1) and p2(a2) of obtaining the value a sub n in the state |psi1> and |psi2> respectively in terms of only phi sub i and psi sub 1(or 2)
 
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If I understand your question-

You can't work out the probabilities from knowledge of the eigenvalues of an operator.
 
christianjb said:
If I understand your question-

You can't work out the probabilities from knowledge of the eigenvalues of an operator.

But the probability that a measurement yields a particular eigenvalue can be expressed in terms of the associated eigenstate and the state of the system, which, if I have interpreted the original post correctly, kac9 has given.

kac9: I'm having trouble guiding you to the answer without just writing down the answer. This is a basic postulate of (shut up and calculate) quantum mechanics. It must be in your notes and text. If you're using Griffiths, it's equation [3.43].
 
George: Ah yes, the state is either in psi1 or psi2- my mistake.
 
Well- a hint would be to write down the identity operator in terms of |phi>

I=sum_i |phi_i><phi_i|

|psi_1>=I|psi_1>
 

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