A rough (as in I haven't stepped through all of the work in the detail you'd need to turn in on an assignment).
First, complete the square to write your quadratic in [tex]X[/tex] as
[tex]
a(X + B)^2 + C[/tex]
(note that [tex]B, C[/tex] are not the same numbers as the [tex]b, c[/tex] in your post.
Since [tex]X \sim \text{n}(0,\sigma^2)[/tex] we can say
[tex]
\begin{align*}<br />
X + B & \sim \text{n}(B,\sigma^2)\\<br />
(X+B)^2 & \sim \chi^2(\delta)\\<br />
\intertext{(non-central chi-square)}<br />
\end{align*}[/tex]
In the end the expression the distribution
[tex]
a(X+B)^2 + C[/tex]
can be described as a scaled (because of the multiplication by [tex]a[/tex]) and translated (due to the addition of [tex]C[/tex]) noncentral chi-square. There is no name for this.
An alternate approach would be to attempt to calculate the characteristic function for your quadratic expression, then attempt inverting. I looked at that: it seemed less than exciting.