Hello! I need help on yet another probability question.. Question: A red dice has the number 1 on one face, the number 2 on two faces and the number 3 on three faces. Two green dice each has the number 6 on one face and the number 5 on five faces. The three dice are thrown together. Calculate the probability of obtaining 2 on the red dice, 5 and 6 on the two green dice. I know that... P(2 on red dice)= 2/6 P(5 and 6 on the two green dice) = 2(5/6 X 1/6) = 5/18 But here's where my confusion sprouts from. The different possible outcomes are: 2 on red, 5 on G-1 and 6 on G-2, or 2 on red, 5 on G-2 and 6 on G-1. where G-1 and G-2 are the green dices. I'm not sure if (A)I should count the "2 on red" once, since the events for the red dice are independent of the other dices,i.e. P(obtaining 2 on red,5 and 6 on green dice) = 2/6 X 5/18 = 5/54 Or (B)Add the probabilities of the possible outcomes together, which will get me... P(obtaining 2 on red,5 and 6 on green dice) = 2(2/6 X 5/18) = 5/27 Sorry if this post is confusing..