Probability Formula Help: Finding P(B|A) with Given Probabilities

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To find P(B|A) given P(A) = 0.7, P(B) = 0.5, and P([A U B]') = 0.1, the correct formula is P(B|A) = P(A ∩ B) / P(A). The discussion highlights the need to determine P(A ∩ B) using the relationship P(A U B) = P(A) + P(B) - P(A ∩ B). Since P([A U B]') = 0.1, it follows that P(A U B) = 0.9. By rearranging the equations, P(A ∩ B) can be calculated, leading to the final answer of P(B|A) = 3/7. Understanding these probability relationships is crucial for solving conditional probability problems.
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Homework Statement



P(A) = .7
P(B) = .5
P( [A U B]' ) = .1

Find: P(B|A)

The answer is 3/7


Homework Equations



P(B|A) = [P(B intersection A)] / [P(B)]

The Attempt at a Solution



I know the formula:

P(B|A) = [P(B intersection A)] / [P(B)]

but how do I find P(B intersection A)] ?

any help would be greatly appreciated.

Thanks
 
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Is there a formula for P(A \cup B) that has P(A \cap B) in it?
 
Yeah,


P(A U B) = P(A) + P(B) - P(A intersect B)
 
That's the one. Now how can you find P(A U B) with the information you are given?
 
i don't know. Thats what i got stuck on
 
I need P(B intersect A)

P(B intersect A) = P(A) + P(B) - P(B U A)


but i don't know how to find P(B U A)
 
If you knew P(X') could you find P(X)?
 
Yeah,

P(X') = 1 - P(X)
 
And you are given that P([A U B]') = .1, so what is P([A U B])? Now what is P(A intersect B), and finally what is P(B|A)?

edit... You wrote the formula for P(B|A) incorrect. It should be P(B|A) = \dfrac{P(A\cap B)}{P(A)}.
 
Last edited:

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