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66% of adults have health insurance, what is the probability that 4 adults selected at random have health insurance?
The probability that four adults selected at random have health insurance, given that 66% of adults possess health insurance, is calculated using the formula (0.66)^4. This results in a probability of approximately 0.1877, or 18.77%. This calculation assumes a large population size, which allows for the use of the binomial probability formula without adjustments for finite population effects.
PREREQUISITESStatisticians, data analysts, health economists, and anyone interested in understanding the probabilities related to health insurance coverage among populations.