MHB Probability of 4 Adults Having Health Insurance

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The probability that four randomly selected adults have health insurance, given that 66% of adults are insured, is calculated using the formula (0.66)^4. This results in a probability of approximately 0.1877, or 18.77%. The assumption is based on a very large population size, which allows for the use of the binomial probability model. The calculation reflects the likelihood of all four individuals being insured under the given percentage. Understanding this probability can help in assessing health insurance coverage among small groups.
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66% of adults have health insurance, what is the probability that 4 adults selected at random have health insurance?
 
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Assuming this is from a very large population (and we have to since we not given the size of the population), that would be (0.6)^4.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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