Probability of a Particle in a box location

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SUMMARY

The discussion focuses on calculating the probability of finding a particle in a one-dimensional box of length L, specifically in its ground state. The probability is determined using the integral of the wavefunction squared, \(\psi^2\), from 0 to L/4, leading to a result of 4/L after normalization. The normalization condition requires that the integral of \(\psi^* \psi\) over the entire box equals 1. Additionally, the expectation values for position, momentum, and kinetic energy are derived from the normalized wavefunction, \(\psi = \sin\frac{n\pi x}{L}\).

PREREQUISITES
  • Quantum mechanics fundamentals, including wavefunctions and probability density
  • Understanding of normalization conditions for wavefunctions
  • Familiarity with expectation values in quantum mechanics
  • Basic calculus for evaluating integrals
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  • Study expectation values and their significance in quantum systems
  • Explore the concept of kinetic energy in quantum mechanics
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Students and educators in quantum mechanics, particularly those tackling problems related to particle-in-a-box models and wavefunction normalization.

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Homework Statement


A particle of mass m is located in a box of length L and found to be in its ground state

A) what is the probability of finding the particle between x=0 and x=L/4
B) What is the expectation value for the position of the particle?
C)What is the expectation value <x^2>?
D)What is the kinetic energy of the particle?
E) What are the 2 possible momentum values for the particle
F)What is the expectation value for momentum
G)what is the expectation value <p^2>?



Homework Equations


Probability= the integral from 0 to L/4 of \psi squared, dx
sin^2((pi)x/L)=1-cos(2(pi)x/L)

The Attempt at a Solution


My attempt at this solution doesn't have a coefficient in front of the integral like my book does in the example it has. I don't know where that one came from and don't know what to put in front of mine for a the book has (2/L) is that like the portion of the box that is being evaluated over? All of the questions above need the question before last to answer starting with the probability. I just need some help getting started and maybe a little more along the way.
 
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It looks like your wavefunction

\psi = \sin\frac{n\pi x}{L}

is not normalized. Something like the coefficient you mention will appear if you normalize this.
 
so how/where would i begin normalizing that??
 
You need \int \psi^* \psi=1[/tex]
 
ok so if the particle is supposed to be in between 0 and L/4 then I'm going to get 4/L because it is 1/4 of the total length of the box...
 
Normalization is the statement that the probability of finding the particle anywhere in the box is 1. That means the normalization integral is over the whole box.
 
That's a reasonable assumption, try the integration and see if it works out that way.
 

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